Hi Michel,

What about
rep(1:10, each=43)

If you need to have characters, you could do something like: as.character(1:10)

HTH,
Ivan

--
Ivan Calandra, ATER
University of Reims Champagne-Ardenne
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51100 Reims, France
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ivan.calan...@univ-reims.fr
https://www.researchgate.net/profile/Ivan_Calandra

Le 11/12/14 11:12, Arnaud Michel a écrit :
Hello
I would like to find an elegant way of calculating
c(rep("1", 43), rep("2",43),...., rep("10",43))

Any idea ?
Thank you


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