On Mon, Aug 4, 2014 at 4:53 AM, raz <barvazd...@gmail.com> wrote:
> Dear all,
>
> I have a data frame 144 x 20000 values.
> I need to take every value in the first row and compare to the second row,
> and the same for rows 3-4 and 5-6 and so on.
> the output should be one line for each of the two row comparison.
> the comparison is:
> if row1==1 and row2==1 <-'HT'
> if row1==1 and row2==0 <-'A'
> if row1==0 and row2==1 <-'B'
> if row1==1 and row2=='-' <-'Aht'
> if row1=='-' and row2==1 <-'Bht'
>
> for example:
> if the data is:
> CloneID genotype 2001 genotype 2002 genotype 2003
> 2471250 1 1 1
> 2471250 0 0 0
> 2433062 0 0 0
> 2433062 1 1 1
> 100021605 1 1 0
> 100021605 1 0 1
> 100005599 1 1 0
> 100005599 1 1 1
> 100002798 1 1 0
> 100002798 1 1 1
>
> then the output should be:
> CloneID genotype 2001 genotype 2002 genotype 2003
> 2471250 A A A
> 2433062 B B B
> 100021605 HT A B
> 100005599 HT HT B
> 100002798 HT HT B
>
> I tried this for the whole data, but its so slow:
>
> AX <- data.frame(lapply(AX, as.character), stringsAsFactors=FALSE)
>
>
> for (i in seq(1,nrow(AX),by=2)){
> for (j in 6:144){
> if (AX[i,j]==1 & AX[i+1,j]==0){
> AX[i,j]<-'A'
> }
> if (AX[i,j]==0 & AX[i+1,j]==1){
> AX[i,j]<-'B'
> }
> if (AX[i,j]==1 & AX[i+1,j]==1){
> AX[i,j]<-'HT'
> }
> if (AX[i,j]==1 & AX[i+1,j]=="-"){
> AX[i,j]<-'Aht'
> }
> if (AX[i,j]=="-" & AX[i+1,j]==1){
> AX[i,j]<-'Bht'
> }
> }
> }
>
> AX1<-AX[!duplicated(AX[,3]),]
> AX2<-AX[duplicated(AX[,3]),]
>
> Thanks for any help,
>
> Raz
I don't know if you've received a solution as yet. Below is my generic
solution. I don't know how fast it will be, but it does _NOT_ do any
looping. It does do a few if functions. The result is in the variable
new_data. The variables data_odd and data_even are temporaries which
can be removed. Or you can wrap the code up in a function which
returns new_data and they will simply "go away" when the function
ends.
#
# Read in the data
data <- read.csv(file="data.csv",header=TRUE,stringsAsFactors=FALSE);
#
# The criteria
#if row1==1 and row2==1 <-'HT'
#if row1==1 and row2==0 <-'A'
#if row1==0 and row2==1 <-'B'
#if row1==1 and row2=='-' <-'Aht'
#if row1=='-' and row2==1 <-'Bht'
#
# The following assumes that data is properly ordered!
data$rowNumber <- seq(1:nrow(data));
data_odd <-data[data$rowNumber %% 2 == 1,];
data_even <-data[data$rowNumber %% 2 == 0,];
#
# You really need to make sure that
# the CloneID values are correct in data_odd
# and data_even. Something like:
stopifnot(data_odd$CloneID == data_even$CloneID);
CloneIDs <- data_even[,1]; # Get the list of CloneIDs
#data_even[,1] <- NULL; # Remove CloneIDs from even data
#data_odd[,1] <- NULL; # And also from odd data
#
# Initialize new_data - make everything NA so
# it will stick out later!
new_data <- data_even;
new_data[,colnames(data_even)] <- NA;
#
new_data[data_odd == 1 & data_odd ==1] <- 'HT';
new_data[data_odd == 1 & data_even == 0] <- 'A';
new_data[data_odd == 0 & data_even == 1] <- 'B';
new_data[data_odd == 1 & data_even == '.'] <- 'Aht';
new_data[data_odd == '-' & data_even == 1] <- 'Bht';
new_data$CloneID <- CloneIDs;
new_data$rowNumber<-NULL;
#
#stopifnot( !is.na(new_data)); # Make sure no NAs left
--
There is nothing more pleasant than traveling and meeting new people!
Genghis Khan
Maranatha! <><
John McKown
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
