Hi,
It is better to show example data using ?dput().
dat <- structure(list(row.names = 1:4, XYZ = c("sample", "sample2",
"sample3", "sample4"), `000_001` = c("sample", "Au5", "C", "C"
), `000_002` = c("sample", "Au32", "C", "Au4"), `000_003` = c("sample",
"Au5", "A", "AC")), .Names = c("row.names", "XYZ", "000_001",
"000_002", "000_003"), class = "data.frame", row.names = c(NA,
-4L))
dat[,intersect(grep("Au5", dat), grep("\\bC\\b",dat)),drop=FALSE]
# 000_001
#1 sample
#2 Au5
#3 C
#4 C
A.K.
On Tuesday, April 29, 2014 9:45 AM, "pascalbe...@libero.it"
<pascalbe...@libero.it> wrote:
Hello,
thank you for accepting me into the list.
I have the following dataframe:
row.names X Y Z 000_001 000_002 000_003
1 sample sample sample sample
2 sample2 Au5 Au32 Au5
3 sample3 C C C
4 ...........
..
..n ............ .... .......
............
I would like to select al the columns that have Au5 and C.
thank you in advance for your help,
james
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