I was under the impression that
do.call(foo,list(x=x,y=y))
should yield the same result as
foo(x,y).
However if I do
x <- 1:10
y <- (x-5.5)^2
do.call(plot,list(x=x,y=y))
I get the expected plot but with the y-values (surrounded by c()) being
printed (vertically) in the left-hand margin of the plot.
The help for do.call() says:
The behavior of some functions, such as substitute, will not be the
same for functions evaluated using do.call as if they were evaluated
from the interpreter. The precise semantics are currently undefined and
subject to change.
Am I being bitten by an instance of this phenomenon? Seems strange.
I would be grateful for enlightenment.
cheers,
Rolf Turner
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