If the data are two week intervals, the frequency is 52/2 = 26
and that matches the amount of data 8*26=208:
> vec.ts <- ts(vec, start=c(2005, 1), frequency=26)
> str(vec.ts)
Time-Series [1:208] from 2005 to 2013: 1 0 0 0 1 1 1 0 2 0 ...
> print(vec.ts, calendar=TRUE)
p1 p2 p3 p4 p5 p6 p7 p8 p9 p10 p11 p12 p13 p14 p15 p16
2005 1 0 0 0 1 1 1 0 2 0 1 0 3 1 1 2
2006 1 0 1 0 0 1 1 0 1 0 1 1 0 0 3 0
2007 1 0 0 0 3 0 1 1 1 0 0 0 1 0 0 0
2008 0 1 0 1 0 1 0 1 1 0 0 0 1 0 0 1
2009 0 1 1 0 0 0 0 2 0 1 1 0 0 2 0 0
2010 1 0 1 1 0 2 0 1 1 0 1 0 0 0 1 1
2011 1 0 1 0 0 1 1 1 2 0 1 1 1 0 0 2
2012 1 0 0 0 0 1 2 0 0 1 0 0 0 2 1 1
p17 p18 p19 p20 p21 p22 p23 p24 p25 p26
2005 0 0 1 0 0 0 3 0 2 0
2006 0 3 1 1 1 0 1 1 0 1
2007 0 2 0 0 1 0 0 0 2 1
2008 0 0 1 1 0 1 0 2 0 2
2009 0 0 1 0 0 1 1 0 1 0
2010 0 0 0 0 0 0 0 0 0 0
2011 0 0 0 0 1 1 1 0 1 0
2012 0 0 0 0 0 1 1 1 1 0
But str() seems to round up on the year for some reason.
-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352
-----Original Message-----
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Michael
Friendly
Sent: Thursday, February 20, 2014 2:04 PM
To: R-help
Subject: [R] bi-monthly time series
The vector, vec, below represents a time series of the number of
some
events recorded
for 208 two-week intervals from 2005/01/01 up to the end of
2012. I
want to
represent this together with the date information. I tried
ts(), but
don't quite understand
how to use the start=, end= and frequency= arguments in this
case.
vec <- c(
1L, 0L, 0L, 0L, 1L, 1L, 1L, 0L, 2L, 0L, 1L, 0L, 3L, 1L, 1L,
2L, 0L, 0L, 1L, 0L, 0L, 0L, 3L, 0L, 2L, 0L, 1L, 0L, 1L, 0L, 0L,
1L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 3L, 0L, 0L, 3L, 1L, 1L, 1L,
0L, 1L, 1L, 0L, 1L, 1L, 0L, 0L, 0L, 3L, 0L, 1L, 1L, 1L, 0L, 0L,
0L, 1L, 0L, 0L, 0L, 0L, 2L, 0L, 0L, 1L, 0L, 0L, 0L, 2L, 1L, 0L,
1L, 0L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 0L,
0L, 1L, 1L, 0L, 1L, 0L, 2L, 0L, 2L, 0L, 1L, 1L, 0L, 0L, 0L, 0L,
2L, 0L, 1L, 1L, 0L, 0L, 2L, 0L, 0L, 0L, 0L, 1L, 0L, 0L, 1L, 1L,
0L, 1L, 0L, 1L, 0L, 1L, 1L, 0L, 2L, 0L, 1L, 1L, 0L, 1L, 0L, 0L,
0L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 1L, 0L, 1L,
0L, 0L, 1L, 1L, 1L, 2L, 0L, 1L, 1L, 1L, 0L, 0L, 2L, 0L, 0L, 0L,
0L, 1L, 1L, 1L, 0L, 1L, 0L, 1L, 0L, 0L, 0L, 0L, 1L, 2L, 0L, 0L,
1L, 0L, 0L, 0L, 2L, 1L, 1L, 0L, 0L, 0L, 0L, 0L, 1L, 1L, 1L, 1L,
0L)
This is what I tried, but it doesn't seem right because str()
reports
... to 2014.
> vec.ts <- ts(vec,
+ start=c(2005,1),
+ frequency=24
+ )
>
> str(vec.ts)
Time-Series [1:208] from 2005 to 2014: 1 0 0 0 1 1 1 0 2 0 ...
>
If instead of a time series, I attached date names to the
observations,
they would be something
like
names(vect) <-
seq(as.Date('2005/01/01'),as.Date('2013/01/01'),by=14)
but that's awkward to work with.
--
Michael Friendly Email: friendly AT yorku DOT ca
Professor, Psychology Dept. & Chair, Quantitative Methods
York University Voice: 416 736-2100 x66249 Fax: 416
736-5814
4700 Keele Street Web: http://www.datavis.ca
Toronto, ONT M3J 1P3 CANADA
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
