Hi Veepsirtt, May be this helps: dat1 <- structure(list(V2 = c(11109.75, 11135.15, 11105.85, 11099.75, 11055.55, 11063.45, 11045.65, 11065, 11061.2, 11070.25, 11069.3, 11076, 11081.85, 11086.4, 11086.7, 11065.6, 11071.25, 11073.15, 11077.8, 11067.7, 11061.1, 11065.9, 11069.1, 11063.3, 11070.45, 11074.4, 11069.4, 11063.65, 11067.05, 11070.1, 11074, 11069.6, 11072.65, 11073.7, 11061.35, 11064.2, 11066.85, 11078.15, 11079.65, 11079.5, 11075.9, 11066.95, 11072.55, 11068.85, 11073.5, 11067.6, 11055.3, 11053.3, 11052.65, 11047.6, 11045.25, 11028.9, 11036.15, 11034.3, 11044.05, 11030.65, 11036.6, 11039.75, 11035.35, 11019.05 )), .Names = "V2", class = "data.frame", row.names = c(NA, 60L )) dat1[seq(5,nrow(dat1),by=5),,drop=FALSE] #or dat1[((seq(nrow(dat1))-1)%%5+1)==5,,drop=FALSE]
A.K. On Sunday, January 19, 2014 9:40 AM, "[email protected]" <[email protected]> wrote: Hi A.K sir 1,11109.75 2,11135.15 3,11105.85 4,11099.75 5,11055.55 6,11063.45 7,11045.65 8,11065 9,11061.2 10,11070.25 11,11069.3 12,11076 13,11081.85 14,11086.4 15,11086.7 16,11065.6 17,11071.25 18,11073.15 19,11077.8 20,11067.7 21,11061.1 22,11065.9 23,11069.1 24,11063.3 25,11070.45 26,11074.4 27,11069.4 28,11063.65 29,11067.05 30,11070.1 31,11074 32,11069.6 33,11072.65 34,11073.7 35,11061.35 36,11064.2 37,11066.85 38,11078.15 39,11079.65 40,11079.5 41,11075.9 42,11066.95 43,11072.55 44,11068.85 45,11073.5 46,11067.6 47,11055.3 48,11053.3 49,11052.65 50,11047.6 51,11045.25 52,11028.9 53,11036.15 54,11034.3 55,11044.05 56,11030.65 57,11036.6 58,11039.75 59,11035.35 60,11019.05 thanks veepsirtt _____________________________________ Sent from http://r.789695.n4.nabble.com ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
