Hi Janet, You may also check library(xts). mod.sage <- read.table(text="date year month day wy yd wyd modQ 1 1965-10-01 1965 10 1 1966 274 1 0.3341630 2 1965-10-02 1965 10 2 1966 275 2 0.3223247 3 1965-10-03 1965 10 3 1966 276 3 0.3459057 4 1965-10-04 1965 10 4 1966 277 4 0.3841630 5 1965-10-05 1965 10 5 1966 278 5 0.3423247 6 1965-10-06 1965 10 6 1966 279 6 0.3209057 7 1966-10-04 1966 10 4 1967 277 4 0.3341630 8 1966-10-05 1966 10 5 1967 278 5 0.3223247 9 1966-10-06 1966 10 6 1967 279 6 0.3109057",sep="",header=TRUE,stringsAsFactors=FALSE)
library(xts) # xt1 <- xts(mod.sage[,-1],order.by=as.Date(mod.sage[,1])) # plot(with(xt1["/1965"],modQ), main= "Year 1965") xt2 <- xts(mod.sage[,-c(1:7)],order.by=as.Date(mod.sage[,1])) plot(xt2["/1965"],main="Year 1965") A.K. On Monday, January 13, 2014 7:41 PM, Janet Choate <[email protected]> wrote: Hi R community, i have a data frame of streamflow for 23 years, i.e. date year month day wy yd wyd modQ 1 1965-10-01 1965 10 1 1966 274 1 0.3341630 2 1965-10-02 1965 10 2 1966 275 2 0.3223247 3 1965-10-03 1965 10 3 1966 276 3 0.3109057 i only want to plot 1 of the years, along with the date. i can accomplish this with: plot(mod.sage$date[mod.sage$wy==1976],mod.sage$modQ[mod.sage$wy==1976], type="l") however, this is a bit long and clunky. is there a way to plot just a portion of the full data record without creating a whole new object with subset? thank you for any help! Janet [[alternative HTML version deleted]] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
