David Winsemius <dwinsemius <at> comcast.net> writes:
> So what happens if you try this:
>
> mapply(assign, kkk$vars, kkk$vals, MoreArgs = list(envir = .GlobalEnv)
>
Yes, it works in certain situations, as well as the equivalent code:
kkk <- data.frame(vars=c("var1", "var2", "var3"),
vals=c(10, 20, 30), stringsAsFactors=F)
mapply(assign, kkk$vars, kkk$vals, MoreArgs = list(pos = 1))
var1
[1] 10
See, however, the following example
: example <- function () {
var1 <- 250
kkk <- data.frame(vars=c("var1", "var2", "var3"),
vals=c(10, 20, 30), stringsAsFactors=F)
mapply(assign, kkk$vars, kkk$vals, MoreArgs = list(pos = 1))
print (var2)
print (var1)
}
example()
[1] 20
[1] 250
My question is: how to get the combination of mapply and assign to affect
the variables defined in the block where the construction is executed?
Maybe there is still something I don't understand.
Thanks,
-Sergio.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
