Did you not see Mark Leeds's post?
The OP apparently did not really mean R's "ordered factors" as
produced by the R ordered() constructor; rather, he meant "factors
with levels ordered differently than the default", for which Rich's
answer was apropos. Mine -- and now yours -- in which we wrongly
assumed the OP knew what he was saying by "ordered factor", was not.
-- Bert
On Mon, Dec 2, 2013 at 11:51 AM, Robert Baer <rb...@atsu.edu> wrote:
>
> On 12/2/2013 9:35 AM, Bert Gunter wrote:
>
> Not true, Rich.
>
> The point about alphabetical ordering explains why the author likely
> explicitly set the levels for the factor, though.
>
> As to why ordered factors, we may never know, but one possible explanation
> is that at some point he was going to use statistics where he wanted to use
> polynomial contrasts. See
>
> options()$contrasts
>
> Note that the default contrast type differs for normal factors and ordered
> factors.
>
>
>
> z <-factor(letters[1:3],lev=letters[3:1])
> sort(z)
>
> [1] c b a
> Levels: c b a
>
> What you say is true only for the **default** sort order.
>
> (Although maybe the code author didn't realize this either)
>
> -- Bert
>
>
> On Mon, Dec 2, 2013 at 7:24 AM, Richard M. Heiberger <r...@temple.edu> wrote:
>
> If days of the week is not an Ordered Factor, then it will be sorted
> alphabetically.
> Fr Mo Sa Su Th Tu We
>
> Rich
>
> On Mon, Dec 2, 2013 at 6:24 AM, Bill <william...@gmail.com> wrote:
>
> I am reading the code below. It acts on a csv file called dodgers.csv with
> the following variables.
>
>
> print(str(dodgers)) # check the structure of the data frame
>
> 'data.frame': 81 obs. of 12 variables:
> $ month : Factor w/ 7 levels "APR","AUG","JUL",..: 1 1 1 1 1 1 1 1 1
> 1 ...
> $ day : int 10 11 12 13 14 15 23 24 25 27 ...
> $ attend : int 56000 29729 28328 31601 46549 38359 26376 44014 26345
> 44807 ...
> $ day_of_week: Factor w/ 7 levels "Friday","Monday",..: 6 7 5 1 3 4 2 6 7
> 1 ...
> $ opponent : Factor w/ 17 levels "Angels","Astros",..: 13 13 13 11 11 11
> 3 3 3 10 ...
> $ temp : int 67 58 57 54 57 65 60 63 64 66 ...
> $ skies : Factor w/ 2 levels "Clear ","Cloudy": 1 2 2 2 2 1 2 2 2 1
> ...
> $ day_night : Factor w/ 2 levels "Day","Night": 1 2 2 2 2 1 2 2 2 2 ...
> $ cap : Factor w/ 2 levels "NO","YES": 1 1 1 1 1 1 1 1 1 1 ...
> $ shirt : Factor w/ 2 levels "NO","YES": 1 1 1 1 1 1 1 1 1 1 ...
> $ fireworks : Factor w/ 2 levels "NO","YES": 1 1 1 2 1 1 1 1 1 2 ...
> $ bobblehead : Factor w/ 2 levels "NO","YES": 1 1 1 1 1 1 1 1 1 1 ...
> NULL
>
> I don't understand why the author of the code decided to make the factor
> days_of_week into an ordered factor. Anyone know why this should be done?
> Thank you.
>
> Here is the code:
>
> # Predictive Model for Los Angeles Dodgers Promotion and Attendance
>
> library(car) # special functions for linear regression
> library(lattice) # graphics package
>
> # read in data and create a data frame called dodgers
> dodgers <- read.csv("dodgers.csv")
> print(str(dodgers)) # check the structure of the data frame
>
> # define an ordered day-of-week variable
> # for plots and data summaries
> dodgers$ordered_day_of_week <- with(data=dodgers,
> ifelse ((day_of_week == "Monday"),1,
> ifelse ((day_of_week == "Tuesday"),2,
> ifelse ((day_of_week == "Wednesday"),3,
> ifelse ((day_of_week == "Thursday"),4,
> ifelse ((day_of_week == "Friday"),5,
> ifelse ((day_of_week == "Saturday"),6,7)))))))
> dodgers$ordered_day_of_week <- factor(dodgers$ordered_day_of_week,
> levels=1:7,
> labels=c("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun"))
>
> # exploratory data analysis with standard graphics: attendance by day of
> week
> with(data=dodgers,plot(ordered_day_of_week, attend/1000,
> xlab = "Day of Week", ylab = "Attendance (thousands)",
> col = "violet", las = 1))
>
> # when do the Dodgers use bobblehead promotions
> with(dodgers, table(bobblehead,ordered_day_of_week)) # bobbleheads on
> Tuesday
>
> # define an ordered month variable
> # for plots and data summaries
> dodgers$ordered_month <- with(data=dodgers,
> ifelse ((month == "APR"),4,
> ifelse ((month == "MAY"),5,
> ifelse ((month == "JUN"),6,
> ifelse ((month == "JUL"),7,
> ifelse ((month == "AUG"),8,
> ifelse ((month == "SEP"),9,10)))))))
> dodgers$ordered_month <- factor(dodgers$ordered_month, levels=4:10,
> labels = c("April", "May", "June", "July", "Aug", "Sept", "Oct"))
>
> # exploratory data analysis with standard R graphics: attendance by month
> with(data=dodgers,plot(ordered_month,attend/1000, xlab = "Month",
> ylab = "Attendance (thousands)", col = "light blue", las = 1))
>
> # exploratory data analysis displaying many variables
> # looking at attendance and conditioning on day/night
> # the skies and whether or not fireworks are displayed
> library(lattice) # used for plotting
> # let us prepare a graphical summary of the dodgers data
> group.labels <- c("No Fireworks","Fireworks")
> group.symbols <- c(21,24)
> group.colors <- c("black","black")
> group.fill <- c("black","red")
> xyplot(attend/1000 ~ temp | skies + day_night,
> data = dodgers, groups = fireworks, pch = group.symbols,
> aspect = 1, cex = 1.5, col = group.colors, fill = group.fill,
> layout = c(2, 2), type = c("p","g"),
> strip=strip.custom(strip.levels=TRUE,strip.names=FALSE, style=1),
> xlab = "Temperature (Degrees Fahrenheit)",
> ylab = "Attendance (thousands)",
> key = list(space = "top",
> text = list(rev(group.labels),col = rev(group.colors)),
> points = list(pch = rev(group.symbols), col = rev(group.colors),
> fill = rev(group.fill))))
>
> # attendance by opponent and day/night game
> group.labels <- c("Day","Night")
> group.symbols <- c(1,20)
> group.symbols.size <- c(2,2.75)
> bwplot(opponent ~ attend/1000, data = dodgers, groups = day_night,
> xlab = "Attendance (thousands)",
> panel = function(x, y, groups, subscripts, ...)
> {panel.grid(h = (length(levels(dodgers$opponent)) - 1), v = -1)
> panel.stripplot(x, y, groups = groups, subscripts = subscripts,
> cex = group.symbols.size, pch = group.symbols, col = "darkblue")
> },
> key = list(space = "top",
> text = list(group.labels,col = "black"),
> points = list(pch = group.symbols, cex = group.symbols.size,
> col = "darkblue")))
>
> # specify a simple model with bobblehead entered last
> my.model <- {attend ~ ordered_month + ordered_day_of_week + bobblehead}
>
> # employ a training-and-test regimen
> set.seed(1234) # set seed for repeatability of training-and-test split
> training_test <- c(rep(1,length=trunc((2/3)*nrow(dodgers))),
> rep(2,length=(nrow(dodgers) - trunc((2/3)*nrow(dodgers)))))
> dodgers$training_test <- sample(training_test) # random permutation
> dodgers$training_test <- factor(dodgers$training_test,
> levels=c(1,2), labels=c("TRAIN","TEST"))
> dodgers.train <- subset(dodgers, training_test == "TRAIN")
> print(str(dodgers.train)) # check training data frame
> dodgers.test <- subset(dodgers, training_test == "TEST")
> print(str(dodgers.test)) # check test data frame
>
> # fit the model to the training set
> train.model.fit <- lm(my.model, data = dodgers.train)
> # obtain predictions from the training set
> dodgers.train$predict_attend <- predict(train.model.fit)
>
> # evaluate the fitted model on the test set
> dodgers.test$predict_attend <- predict(train.model.fit,
> newdata = dodgers.test)
>
> # compute the proportion of response variance
> # accounted for when predicting out-of-sample
> cat("\n","Proportion of Test Set Variance Accounted for: ",
> round((with(dodgers.test,cor(attend,predict_attend)^2)),
> digits=3),"\n",sep="")
>
> # merge the training and test sets for plotting
> dodgers.plotting.frame <- rbind(dodgers.train,dodgers.test)
>
> # generate predictive modeling visual for management
> group.labels <- c("No Bobbleheads","Bobbleheads")
> group.symbols <- c(21,24)
> group.colors <- c("black","black")
> group.fill <- c("black","red")
> xyplot(predict_attend/1000 ~ attend/1000 | training_test,
> data = dodgers.plotting.frame, groups = bobblehead, cex = 2,
> pch = group.symbols, col = group.colors, fill = group.fill,
> layout = c(2, 1), xlim = c(20,65), ylim = c(20,65),
> aspect=1, type = c("p","g"),
> panel=function(x,y, ...)
> {panel.xyplot(x,y,...)
> panel.segments(25,25,60,60,col="black",cex=2)
> },
> strip=function(...) strip.default(..., style=1),
> xlab = "Actual Attendance (thousands)",
> ylab = "Predicted Attendance (thousands)",
> key = list(space = "top",
> text = list(rev(group.labels),col = rev(group.colors)),
> points = list(pch = rev(group.symbols),
> col = rev(group.colors),
> fill = rev(group.fill))))
>
> # use the full data set to obtain an estimate of the increase in
> # attendance due to bobbleheads, controlling for other factors
> my.model.fit <- lm(my.model, data = dodgers) # use all available data
> print(summary(my.model.fit))
> # tests statistical significance of the bobblehead promotion
> # type I anova computes sums of squares for sequential tests
> print(anova(my.model.fit))
>
> cat("\n","Estimated Effect of Bobblehead Promotion on Attendance: ",
> round(my.model.fit$coefficients[length(my.model.fit$coefficients)],
> digits = 0),"\n",sep="")
>
> # standard graphics provide diagnostic plots
> plot(my.model.fit)
>
> # additional model diagnostics drawn from the car package
> library(car)
> residualPlots(my.model.fit)
> marginalModelPlots(my.model.fit)
> print(outlierTest(my.model.fit))
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
>
--
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
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