I think this gives a different result than the one OP asked for:
df1 <- structure(list(ID = c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L), x = c(1, 0,
0, 1, 0, 0, 0, 1, 2, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0)), .Names = c("ID",
"x"), row.names = c(NA, -22L), class = "data.frame")
with(df1, sapply(split(x, ID), function(x) sum(x==0)))
with(df1,tapply(x,list(ID),function(y) {rl <- rle(!y);
max(c(0,rl$lengths[rl$values]))}))
A.K.
On Friday, November 1, 2013 6:01 AM, PIKAL Petr <petr.pi...@precheza.cz> wrote:
Hi
Another option is sapply/split/sum construction
with(data, sapply(split(x, ID), function(x) sum(x==0)))
Regards
Petr
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Carlos Nasher
> Sent: Thursday, October 31, 2013 6:46 PM
> To: S Ellison
> Cc: r-help@r-project.org
> Subject: Re: [R] Count number of consecutive zeros by group
>
> If I apply your function to my test data:
>
> ID <- c(1,1,1,2,2,3,3,3,3)
> x <- c(1,0,0,0,0,1,1,0,1)
> data <- data.frame(ID=ID,x=x)
> rm(ID,x)
>
> f2 <- function(x) {
> max( rle(x == 0)$lengths )
> }
> with(data, tapply(x, ID, f2))
>
> the result is
> 1 2 3
> 2 2 2
>
> which is not what I'm aiming for. It should be
> 1 2 3
> 2 2 1
>
> I think f2 does not return the max of consecutive zeros, but the max of
> any consecutve number... Any idea how to fix this?
>
>
> 2013/10/31 S Ellison <s.elli...@lgcgroup.com>
>
> >
> >
> > > -----Original Message-----
> > > So I want to get the max number of consecutive zeros of variable x
> > > for
> > each
> > > ID. I found rle() to be helpful for this task; so I did:
> > >
> > > FUN <- function(x) {
> > > rles <- rle(x == 0)
> > > }
> > > consec <- lapply(split(df[,2],df[,1]), FUN)
> >
> > You're probably better off with tapply and a function that returns
> > what you want. You're probably also better off with a data frame name
> > that isn't a function name, so I'll use dfr instead of df...
> >
> > dfr<- data.frame(x=rpois(500, 1.5), ID=gl(5,100)) #5 ID groups
> > numbered 1-5, equal size but that doesn't matter for tapply
> >
> > f2 <- function(x) {
> > max( rle(x == 0)$lengths )
> > }
> > with(dfr, tapply(x, ID, f2))
> >
> >
> > S Ellison
> >
> >
> > *******************************************************************
> > This email and any attachments are confidential. Any
> > u...{{dropped:24}}
>
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