Hi, Try: set.seed(49) t(sapply(seq_len(ncol(pro)),function(i) {ids<- runif(1); x1<-cut(ids,breaks=pro[,i]); c(ids=ids,bin_location=x1)})) # ids bin_location #[1,] 0.3656991 1 #[2,] 0.4878542 2
A.K. ----- Original Message ----- From: ioanna ioannou <ii54...@msn.com> To: r-help@r-project.org Cc: Sent: Wednesday, September 18, 2013 8:43 AM Subject: Re: [R] Identifying the bin where a value is included. Hello all, A very simple problem. Lets assume I have an interval [0,1] and I split it in 6 bins having thresholds: pro= cbind(0, 0.3675509, 0.8618615, 0.9814291, 0.9975283, 0.9997789, 1.0000000, 0, 0.3662881, 0.8609743, 0.9812032, 0.9974822, 0.9997738, 1.0000000) dim(pro)<-c(7,2) I randomly generate a number and I want to identify which bin it belongs to. How? What I provide below doesn't seem to be working. Any ideas? for (i in 1:2){ ids<-runif(1) for (j in 1:length(pro[,i])-1){ if (ids < pro[j,i]) { ds[i]<-j } else { ds[i]<-6 } } } Best, IOanna ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.