Hi,
Try: set.seed(49)
t(sapply(seq_len(ncol(pro)),function(i) {ids<- runif(1);
x1<-cut(ids,breaks=pro[,i]); c(ids=ids,bin_location=x1)}))
# ids bin_location
#[1,] 0.3656991 1
#[2,] 0.4878542 2
A.K.
----- Original Message -----
From: ioanna ioannou <ii54...@msn.com>
To: r-help@r-project.org
Cc:
Sent: Wednesday, September 18, 2013 8:43 AM
Subject: Re: [R] Identifying the bin where a value is included.
Hello all,
A very simple problem.
Lets assume I have an interval [0,1] and I split it in 6 bins having
thresholds:
pro= cbind(0, 0.3675509, 0.8618615, 0.9814291, 0.9975283, 0.9997789,
1.0000000,
0, 0.3662881, 0.8609743, 0.9812032, 0.9974822, 0.9997738,
1.0000000)
dim(pro)<-c(7,2)
I randomly generate a number and I want to identify which bin it belongs
to. How? What I provide below doesn't seem to be working.
Any ideas?
for (i in 1:2){
ids<-runif(1)
for (j in 1:length(pro[,i])-1){
if (ids < pro[j,i]) {
ds[i]<-j
}
else {
ds[i]<-6
}
}
}
Best,
IOanna
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and provide commented, minimal, self-contained, reproducible code.
