Here's one way to extend the code to groups of 4 as well ...
Jean
# 3
df2 <- df
names(df2) <- paste0("new", 1:2)
df3 <- merge(df2, df, by.x="new2", by.y="V.1")[, c(2, 1, 3)]
names(df3) <- paste0("new", 1:3)
df3
# 4
df4 <- merge(df3, df, by.x="new3", by.y="V.1")[, c(2, 3, 1, 4)]
names(df4) <- paste0("new", 1:4)
df4
On Mon, Aug 5, 2013 at 2:07 PM, Pierre Khoueiry <pierre.khoue...@embl.de>wrote:
> No no I'am buying it for sure. Thank you very much. It is way better.
>
> Just one issue. I did my code because I wanted indeed triplets but also
> groups of 4, 5 and so on. This is why the nbElements is defined in my code.
>
> My problem I think is that I am using the scripting languages logic in R
> !!! I should
> Thanks,
>
>
>
>
> On 5Aug, 2013, at 21:01 , Adams, Jean wrote:
>
> Hmmm. I'm not sure why you prefer 20-30 lines of looping code over a
> simpler 1 line solution, but, as you wish.
>
> merge(df, df, by.x="V.2", by.y="V.1")[, c(2, 1, 3)]
>
> Jean
>
>
> On Mon, Aug 5, 2013 at 12:37 PM, PQuery <pierre.khoue...@embl.de> wrote:
>
>> Hello Jean,
>>
>> Thanks for the reply. However, you solution doesn't reproduce the output
>> that I desire.
>>
>> I updated my post with my solution full of loops.
>>
>> If there is a more fancy/elegant way, I'll take it.
>>
>> Best,
>>
>>
>>
>> --
>> View this message in context:
>> http://r.789695.n4.nabble.com/obtain-triplets-from-Data-Frame-columns-tp4673091p4673164.html
>> Sent from the R help mailing list archive at Nabble.com.
>>
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>>
>
>
> --
> ========================
> Pierre Khoueiry
> EMBL - Heidelberg
> Furlong group, room V320
> Meyerhofstraße 1,
> 69117 Heidelberg, Germany
> Tel: +49 (0)6221-387 8682
> ========================
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