On Jul 20, 2013, at 10:37 AM, Scott Robinson wrote: > Dear List, > > I have been trying to use p.adjust() to do BH multiple test correction and > have gotten some unexpected results. I thought that the equation for this was: > > pBH = p*n/i
Looking at the code for `p.adjust`, you see that the method is picked from a switch function lp <- length(p) BH = { i <- lp:1L o <- order(p, decreasing = TRUE) ro <- order(o) pmin(1, cummin(n/i * p[o]))[ro] } You may not have sorted the p-values in pList. > > where p is the original p value, n is the number of tests and i is the rank > of the p value. However when I try and recreate the corrected p from my most > significant value it does not match up to the one computed by the method > p.adjust: > >> setwd("C:/work/Methylation/IMA/GM/siteLists") >> >> hypTable <- read.delim("hypernormal vs others.txt") >> pList <- hypTable$p >> names(pList) <- hypTable$site >> >> adjusted <- p.adjust(pList, method="BH") >> adjusted[1] > cg27433479 > 0.05030589 >> >> pList[1]*nrow(hypTable)/1 > cg27433479 > 0.09269194 > No data provided, so unable to pursue this further. > I tried to recreate this is a small example of a vector of 5 p values but > everything worked as expected there. I was wondering if there is some subtle > difference about how p.adjust operates? Is there something more complicated > about how to calculate 'n' or 'i' - perhaps due to identical p values being > assigned the same rank or something? Does anyone have an idea what might be > going on here? -- David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.