I was not clear on exactly what you want to do. I assume that you want to
automate the process given 120 file names. Here is part of a script that
will parse the file names and give you the output file you want. If it is
something different, then clarify your request:
> input <- "C:/RHTests/data/tmax/00032015tmax.csv"
> # parse off the file name
> x <- sub(".*/(.*)", "\\1", input)
> x
[1] "00032015tmax.csv"
> # strip off the leading numbers
> num <- sub("([[:digit:]]+).*", "\\1", x)
> # remove leading zeros and combine back with path
> path <- sub("(.*/).*", "\\1", input)
> output <- paste0(path, as.integer(num), "tmx")
> output
[1] "C:/RHTests/data/tmax/32015tmx"
2013/7/15 RODRIGUEZ MORENO VICTOR MANUEL <rodriguez.vic...@inifap.gob.mx>
> Hello everyone on the list
> I want to run a FindU function on as many files as in a directory. Due of
> my limitations on data management I am calling the function, wait until
> finish the process, call for the next file and so on. I have almost 120 CSV
> files on the same directory. This the example of calling the function
>
> FindU(InSeries="C:/RHTests/data/tmax/00032015tmax.csv",
> MissingValueCode="-99.9", p.lev=0.95, Iadj=10000, Mq=10, Ny4a=0,
> output="C:/RHTests/data/tmax/32015tmx")
> As you can see my input file is "00032015tmax.csv" and my output file is
> "32015tmx".
> Any suggestions? Thanks a lot in advance
>
>
> Dr Victor M Rodríguez M
> Doctor en Ciencias, en Ciencias de la Tierra / Geociencias Ambientales
> INIFAP. CEPAB. (465) 9580167 y 86 Ext 108 y 220
>
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>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
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