Hi,
library(car)
recode(x,"'x'=1;'y'=2;'z'=3")
#[1] 1 1 1 2 2 2 3 3 3
#or
as.numeric(factor(x))
#[1] 1 1 1 2 2 2 3 3 3
A.K.
----- Original Message -----
From: Trevor Davies <davies.tre...@gmail.com>
To: "r-help@r-project.org" <r-help@r-project.org>
Cc:
Sent: Friday, July 12, 2013 5:56 PM
Subject: Re: [R] replace multiple values in vector at once
I always think that replying to your own r-help feels silly but it's good
to close these things out.
here's my hack solution:
x1<-merge(data.frame(A=x),data.frame(A=c('x','y','z'),B=c(1,2,2)),by='A')[,2]
Well that works and should for my more complex situation. If anyone has
something a little less heavy handed I'd live to hear it.
Have a great weekend.
On Fri, Jul 12, 2013 at 2:18 PM, Trevor Davies <davies.tre...@gmail.com>wrote:
>
> I'm trying to find a function that can replace multiple instances of
> values or characters in a vector in a one step operation. As an example,
> the vector:
>
> x <- c(rep('x',3),rep('y',3),rep('z',3))
>
> > x
> [1] "x" "x" "x" "y" "y" "y" "z" "z" "z"
>
> I would simply like to replace all of the x's with 1's, y:2 & z:3 (or
> other characters).
> i.e:
> > x
> [1] "1" "1" "1" "2" "2" "2" "3" "3" "3"
>
> Of course, I'm aware of the replace function but this obviously gets a
> little unwieldy when there are :
> x<-replace(x,x=='x',1)
> x<-replace(x,y=='x',2)
> x<-replace(x,z=='x',3)
>
> but I can't figure out how to do it in a one stop operation. My real
> needs is more complex obviously. This is one of those seemingly simple
> r-operations that should be obvious but I'm coming up empty on this one.
>
> Thanks for the help.
> Trevor
>
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