Hello,
Another possibility is to use the formula interface.
x <- scan(what = "character", text = "
a a a a a b b b c c c c")
y <- scan(text = "
2 4 5 2 7 2 2 6 3 7 9 3")
kruskal.test(y ~ factor(x))
dat <-
structure(list(x = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L,
3L, 3L, 3L, 3L), .Label = c("a", "b", "c"), class = "factor"),
y = c(2, 4, 5, 2, 7, 2, 2, 6, 3, 7, 9, 3)), .Names = c("x",
"y"), row.names = c(NA, -12L), class = "data.frame")
kruskal.test(y ~ x, data = dat)
Hope this helps,
Rui Barradas
Em 09-07-2013 18:48, arun escreveu:
Hi,
?kruskal.test()
a<- c(2,4,5,2,7)
b<- c(2,2,6)
c<- c(3,7,9,3)
kruskal.test(list(a,b,c))
#
# Kruskal-Wallis rank sum test
#
#data: list(a, b, c)
#Kruskal-Wallis chi-squared = 2.003, df = 2, p-value = 0.3673
A.K.
Hi
I need an expression in R to apply a kruskal.test to this data (for example).
a a a a a b b b c c c c
2 4 5 2 7 2 2 6 3 7 9 3
a, b and c could be consider different vectors. How can I apply this
test to this data? (probably the data isn't good to this test, but I
onlu need the expression).
Thank you very much
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and provide commented, minimal, self-contained, reproducible code.
