You might want to use Rprof to profile your code to understand where the time is going; it might be in the function you are callingband therefore the "for" loop might not be the issue.
Sent from my iPad On Jun 27, 2013, at 4:19, "Frederico Mestre" <mestre.freder...@gmail.com> wrote: > Hello: > > > > I have a list of data frames, built like this: the second df is a result of > a function applied to the first, and so on. > > > > So the ith df is always dependent on the (i-1)th df. I've been doing this > using for loops. However I think I have too many for loops which is making > my code run slowly. > > > > Is there any workaround this? How can I avoid the use of for loops? > > > > As an example: > > > > output.list <- as.list(rep("", 100))#creation of a list > > > > output.list[[1]] <- df1#first position > > > > > > for(I in 2:100){#following positions > > > > df0 <- output.list[[i-1]] > > > > df0_1 <- f1(df0)#function applied to the previous df > > > > output.list[[i]] <- df0_1#new df > > > > } > > > > thanks, > > > > Frederico > > > > > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.