Hi, Perhaps this works: a[sapply(b,function(x) which.min(abs(x-a)))] #[1] 8 32
A.K. ----- Original Message ----- From: Andras Farkas <motyoc...@yahoo.com> To: r-help@r-project.org Cc: Sent: Tuesday, June 18, 2013 8:34 AM Subject: [R] find closest value in a vector based on another vector values Dear All, would you please provide your thoughts on the following: let us say I have: a <-c(1,5,8,15,32,69) b <-c(8.5,33) and I would like to extract from "a" the two values that are closest to the values in "b", where the length of this vectors may change but b will allways be shorter than "a". So at the end based on this example I should have the result "f" as f <-c(8,32) appreciate the help, Andras ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
