HI Andras, Sorry, I misunderstood your question: Try this: sapply(sapply(b,function(x) d[x<d]),`[`,1) #[1] 12 36 36
----- Original Message ----- From: Andras Farkas <motyoc...@yahoo.com> To: arun <smartpink...@yahoo.com> Cc: Sent: Monday, June 17, 2013 2:48 PM Subject: Re: [R] vector question Arun, thank you. Looking at it I am wondering if there is a way to get 36 in the result instead of the 24. The 2nd value in b is 24.6, therefore the 1st value greater then that in d is 36. appreciate the help, Andras --- On Mon, 6/17/13, arun <smartpink...@yahoo.com> wrote: > From: arun <smartpink...@yahoo.com> > Subject: Re: [R] vector question > To: "Andras Farkas" <motyoc...@yahoo.com> > Cc: "R help" <r-help@r-project.org> > Date: Monday, June 17, 2013, 2:45 PM > May be this helps: > > d[cumsum(sapply(d,function(x) any(x>b)))>=1] > #[1] 12 24 36 > A.K. > > > ----- Original Message ----- > From: Andras Farkas <motyoc...@yahoo.com> > To: r-help@r-project.org > Cc: > Sent: Monday, June 17, 2013 2:29 PM > Subject: [R] vector question > > Dear All, > > would you please help with the following: > let us say I have: > > a <-c(0,1,12,13,24,25,36,37) > b <-c(6,24.6,27) > #then I extract every 2nd element from "a" > d <-a[seq(1, length(a), 2)] > > and what I need help with is to extract the 1st value from d > that is greater than the values in b, so as a result I > should have "f" as: > > f <-c(12,36,36) > > appreciate the insights, > > thank you, > > Andras > > ______________________________________________ > R-help@r-project.org > mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible > code. > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
