Thankyou very very much arun.....:Delisa
> Date: Fri, 24 May 2013 11:08:56 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] Continuous columns of matrix
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.org; ruipbarra...@sapo.pt
>
> Hi,
> You may also try:
> mat: data
>
> lst1<-lapply(split(mat,col(mat)),function(x) {x1<- which(x>=0.8*max(x));x2<-
> which.max(x);x1[abs(x1-x2)==1|length(x)-abs(x1-x2)==1]<-NA;rbind(index=x1[!is.na(x1)],values=x[x1[!is.na(x1)]])})
> names(lst1)<-NULL
>
> lst2<-apply(mat,2,function(x) do.call(rbind,fun2(x))) #Rui's function
> identical(lst1,lst2)
> #[1] TRUE
> A.K.
>
> ----- Original Message -----
>
> From: eliza botto <eliza_bo...@hotmail.com>
> To: Berend Hasselman <b...@xs4all.nl>
> Cc: "r-help@r-project.org" <r-help@r-project.org>
> Sent: Friday, May 24, 2013 6:41 AM
> Subject: Re: [R] Continuous columns of matrix
>
> There you go!!!
>
> structure(c(0.706461987893674, 0.998391468394261, 0.72402995269242,
> 1.70874688194537, 1.93906363083693, 0.89540353128442, 0.328327645695443,
> 0.427434603701202, 0.591932250254601, 0.444627635494183, 1.44407704434405,
> 1.79150336746345, 0.94525563730664, 1.1025988539757, 0.944726401770203,
> 0.941068515436361, 1.50874009152312, 0.590015480056925, 0.311905493999476,
> 0.596771673581893, 1.01502499067153, 0.803273181849135, 1.6704085033648,
> 1.57021117646422, 0.492096635764151, 0.433332688044914, 0.521585941816778,
> 1.66472272302545, 2.61878329527404, 2.19154489521664, 0.493876245329722,
> 0.4915787202584, 0.889477365620806, 0.609135860199222, 0.739201878930367,
> 0.854663750519518, 0.948228727226247, 1.38569091844218, 0.910510759802679,
> 1.25991218521949, 0.993123416952421, 0.553640392997634, 0.357487763503204,
> 0.368328033777003, 0.344255688489322, 0.423679560916755, 1.32093576037521,
> 3.13420679229785, 2.06195904001605, 1.41493262330451, 1.35748791897328,
> 1.19490680241894, 0.70248875618332!
> 2, 0.338258418490199, 0.123398398622741, 0.138548982660226, 0.16170889185798,
> 0.414543218677095, 1.84629295875002, 2.24547399004563, 0.0849732189580101,
> 0.070591276171845, 0.0926010253161898, 0.362209761457517, 1.45769283057202,
> 3.16165004659667, 2.74903557756267, 1.94633472878995, 1.19319875840883,
> 0.533232612926756, 0.225531074123974, 0.122949089115578), .Dim = c(12L, 6L))
>
> Thanks once again..
> Elisa
>
>
> > Subject: Re: [R] Continuous columns of matrix
> > From: b...@xs4all.nl
> > Date: Fri, 24 May 2013 12:36:47 +0200
> > CC: r-help@r-project.org
> > To: eliza_bo...@hotmail.com
> >
> >
> > On 24-05-2013, at 12:24, eliza botto <eliza_bo...@hotmail.com> wrote:
> >
> > > Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns
> > > are continuous. I want to find the index of maximum values and the
> > > actual maximum values. The maximum values in each column are the highest
> > > values and the values greater than or equal to 80% of the maximum value.
> > > Moreover, if a column has more than one maximum values than these values
> > > should come immediately next to each other. For example, if you column 1
> > > has a highest value in 6th row then the second maximum values cant be in
> > > row 5 or 7. And as the columns are continuous therefore, if maximum value
> > > is in row 12th, then the second maximum cant be in row 11 and 1.Thankyou
> > > very much indeed in advance
> >
> >
> > Incomprehensible.
> > What is a continuous column?
> >
> > Please give an example input matrix and and the result you want.
> >
> > Berend
> >
> > > Elisa
> > > [[alternative HTML version deleted]]
> > >
> >
> > Please post in plain text.
> >
>
> [[alternative HTML version deleted]]
>
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