Hello,
You should keep this on the list, the odds of getting more and better
answers are greater.
I don't know if the following is what you want.
apply(time.m, 2, function(tt) as.POSIXct(tt, format = "%H:%M:%OS"))
Hope this helps,
Rui Barradas
Em 26-04-2013 21:49, hh wt escreveu:
sapply doesn't do it. It just spits out the guts,
$`08:00:20.799.sec`
[1] 20.799
$`08:00:20.799.min`
[1] 0
$`08:00:20.799.hour`
[1] 8
$`08:00:20.799.mday`
[1] 26
$`08:00:20.799.mon`
[1] 3
$`08:00:20.799.year`
[1] 113
On Fri, Apr 26, 2013 at 11:25 AM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
Hello,
Use sapply instead.
Hope this helps,
Rui Barradas
Em 26-04-2013 18:51, hh wt escreveu:
I thought this is a common question but rseek/google searches don't yield
any relevant hit.
I have a matrix of character strings, which are time stamps,
time.m[1:5,1:5]
[,1] [,2] [,3] [,4] [,5]
[1,] "08:00:20.799" "08:00:20.799" "08:00:20.799" "08:00:20.799"
"08:00:20.799"
[2,] "08:00:21.996" "08:00:22.071" "08:00:23.821" "08:00:24.370"
"08:00:25.573"
[3,] "08:00:29.200" "08:00:29.200" "08:00:29.591" "08:00:30.368"
"08:00:30.536"
[4,] "08:00:31.073" "08:00:31.372" "08:00:31.384" "08:00:31.403"
"08:00:31.867"
[5,] "08:00:31.867" "08:00:31.867" "08:00:31.971" "08:00:34.571"
"08:00:34.571"
And i would like to convert it to a POSIXct matrix. I tried this,
time1 = lapply(time.m, function(tt)strptime(tt, "%H:%M:%OS"))
but it yields a list.
Any tip is appreciated.
Horace
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