On Apr 17, 2013, at 10:20 PM, Sachinthaka Abeywardana wrote: > Hi All, > > I have the following problem (read the commented bit below): > > a<-matrix(1:9,nrow=3) > > > a > > [,1] [,2] [,3] > [1,] 1 4 7 > [2,] 2 5 8 > [3,] 3 6 9 > > > div<-1:3 > > apply(a,2,function(x)x/div) ##want to divide each column by div- > instead each row is divided##
No. Each column is divided by that vector 'div'. Try: 1:3/1:3 4:6/1:3 7:9/1:3 > [,1] [,2] [,3] > [1,] 1 4.0 7 > [2,] 1 2.5 4 > [3,] 1 2.0 3 > > > apply(a,1,function(x)x/div) ##Changing Margin from 2 to 1 does > something completele weird## [,1] [,2] [,3] > [1,] 1.000000 2.000000 3 > [2,] 2.000000 2.500000 3 > [3,] 2.333333 2.666667 3 Each row is divided by that vector but then returned as columns. Try it with a matrix that has a different number of columns than rows. -- David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
