Dear John, Thanks for your comments! But when I tried your suggestion, the output was as the following:
 Response Dist_arbre :       Df   Sum Sq   Mean Sq F value   Pr(>F)   Poids     1 0.00010398 0.00010398  6.2910 0.0364733 *  Age      1 0.00005202 0.00005202  3.1476 0.1139652   --- Signif. codes:  0 â***â 0.001 â**â 0.01 â*â 0.05 â.â 0.1 â â 1 I have the P-value but not the direction of the relationship, information that I had with  "lm(as.matrix(Y) ~ x+z)". I could combine the results of these two tests, but it seems inelegant to me. Moreover I didn't have a total significance test as with a true MANCOVA. An idea?! Rémi Lesmerises, biol. M.Sc., Candidat Ph.D. en Biologie Université du Québec à Rimouski 300, allée des Ursulines remilesmeri...@yahoo.ca ________________________________ De : John Fox <j...@mcmaster.ca> à: Rémi Lesmerises <remilesmeri...@yahoo.ca> Cc : "r-help@r-project.org" <r-help@r-project.org> Envoyé le : mercredi 17 avril 2013 10h54 Objet : Re: [R] Mancova with R Dear Remi, Take a look at the Anova() function in the car package. In your case, you could use Anova(lm(as.matrix(Y) ~ x + z)) or, for more detail, summary(Anova(lm(as.matrix(Y) ~ x + z))) I hope this helps, John ------------------------------------------------ John Fox Sen. William McMaster Prof. of Social Statistics Department of Sociology McMaster University Hamilton, Ontario, Canada http://socserv.mcmaster.ca/jfox/    On Wed, 17 Apr 2013 07:47:27 -0700 (PDT) Rémi Lesmerises <remilesmeri...@yahoo.ca> wrote: > Dear all, > > I'm trying to compare two sets of variables, the first set is composed > exclusively of numerical variables and the second regroups factors and > numerical variables. I can't use a Manova because of this inclusion of > numerical variables in the second set. The solution should be to perform a > Mancova, but I didn't find any package that allow this type of test. > > I've already looked in this forum and on the net to find answers, but the > only thing I've found is the following: > > > lm(as.matrix(Y) ~ x+z) > x and z could be numerical and factors. The problem with that is it actually > only perform a succession of lm (or glm), one for each numerical variable > contained in the Y matrix. It is not a true MANCOVA that do a significance > test (most often a Wald test) for the overall two sets comparison. Such a > test is available in SPSS and SAS, but I really want to stay in R! Someone > have any idea? > > Thanks in advance for your help! >  > Rémi Lesmerises, biol. M.Sc., > Candidat Ph.D. en Biologie > Université du Québec à Rimouski > remilesmeri...@yahoo.ca > >    [[alternative HTML version deleted]] > [[alternative HTML version deleted]]
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