see inline



________________________________
 From: PIKAL Petr <petr.pi...@precheza.cz>

Sent: Wednesday, March 27, 2013 1:50 PM
Subject: RE: [R] Averaging Out many rows from a column AND funtion to string



Hi
 

Sent: Wednesday, March 27, 2013 11:46 AM
To: PIKAL Petr; R help
Subject: Re: [R] Averaging Out many rows from a column AND funtion to string
 
see inline
 

________________________________

From:PIKAL Petr <petr.pi...@precheza.cz>

Sent: Wednesday, March 27, 2013 11:24 AM
Subject: RE: [R] Averaging Out many rows from a column AND funtion to string

Hi

> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Alaios
> Sent: Wednesday, March 27, 2013 9:13 AM
> To: R help
> Subject: [R] Averaging Out many rows from a column AND funtion to
> string
> 
> Dear all,
> 1) I have a very large matrix of
> str(keep)
>  num [1:153899, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ...
> that  I would like to reduce its size to something like
> 
> str(keep)
>  num [1:1000, 1:3415] -98.6 -95.8 -96.4 -95.8 -98 ... or anything
> similar in size as this is a matrix that needs plotting (so is ok if it
> is 1000 row, 995, or 1123)
> 
> I think what I need here is a way of selecting multiple rows and
> averaging per column (notice that the column number should stay the
> same)

Make an index variable and aggregate values according it

Something like
idx<-cut(1:153899, 153)
keep.ag<-aggregate(keep, list(idx), mean)

1) Thanks that returned a data frame.. How I can have a matrix at the end?


use as.matrix(data.frame) on numeric part

a bit of my code that you can re run. I convert a 30,30 matrix to a 10,30.  
but it looks at the end that I do not get the Data part of the data.fram 
correctly: 

Data<-matrix(data=rnorm(900,80,20),nrow=30,ncol=30)
idx<-cut(1:30, 10)
keep.ag<-aggregate(Data, list(idx), mean)
str(as.matrix(keep.ag) ) # it does not look like integers









2) I want to have a string that can be used also for calling a function with 
the same name. Think of using "mean" to call mean. I need to have R interpret 
the string in different ways.


To call „mean“ of what? I am sure I do not understand what is your 
intention.
LogFunction<- function(){}
FunctionIndex<- rbind (c(1,"LogFunction"),
               c(2,"TakeFunction"))
print(sprintf('Using the function %s',FunctionIndex[1,1]))
This does not contain much clue.
Regards
Petr
PS. Do not use HTML mail messages. 
Regards
Alex

> 
> b. I would like to be able to convert strings that are function names
> to real function calls. For example I have something like
> 
> LogFunction<- function(){}
> FunctionIndex<- rbind (c(1,"LogFunction"),
>                c(2,"TakeFunction")
>               )
> print(sprintf('Using the function %s',FunctionIndex[1,1])) # call the
> FunctionIndex[1,1] somehow

I am not sure if I understand correctly. 

Is this what you want?
myf <-function(fun="mean", arg) eval(call(fun, arg))

Regards
Petr

> 
> 
> 
> I would like to thank you in advance for your help
> 
> Regards
> Alex
> 
>     [[alternative HTML version deleted]]
        [[alternative HTML version deleted]]

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