Here's a possible solution.
dd <- structure(list(a = c(TRUE, FALSE, FALSE),
b = c(TRUE, FALSE, TRUE),
c = c(TRUE, FALSE, FALSE),
d = c(TRUE, TRUE, FALSE)),
.Names = c("a", "b", "c", "d"),
row.names = c(NA, -3L),
class = "data.frame")
ds <- as.data.frame(t(apply(!dd, 1, cumsum)-apply(dd, 1, cumsum)))
ds[as.matrix(dd)] <- 0
ds
Best,
Nello
-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Camilo Mora
Sent: Mittwoch, 27. März 2013 09:32
To: r-help@r-project.org
Subject: [R] conditional Dataframe filling
Hi everyone:
This may be trivial but I just have not been able to figure it out.
Imagine the following dataframe:
a b c d
TRUE TRUE TRUE TRUE
FALSE FALSE FALSE TRUE
FALSE TRUE FALSE FALSE
I would like to create a new dataframe, in which TRUE gets 0 but if false then
add 1 to the cell to the left. So the results for the example above should be
something like:
a b c d
0 0 0 0
1 2 3 0
1 0 1 2
I wonder if you may know?.
Thanks,
Camilo
Camilo Mora, Ph.D.
Department of Geography, University of Hawaii Currently available in Colombia
Phone: Country code: 57
Provider code: 313
Phone 776 2282
From the USA or Canada you have to dial 011 57 313 776 2282
http://www.soc.hawaii.edu/mora/
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
