On 02/24/2013 02:56 PM, Jannetta Steyn wrote:
Hi All
I'm just wondering if there is a quick way of filling a way with the
following.
I want to declare array I with a specific length and then alternatively
fill it with 10 zeros and 10 specified values:
v<- 14
I<- c(0,length(t))
But in stead of just filling I with 0 I want 10 zeros and then 10 fourteens
(i.e. the value in v)
Hope that makes sense.
Hi Janetta,
It makes some sense, but perhaps not enough. The easy answer would be:
I<-c(rep(0,10),rep(v,10))
If you mean you want _alternating_ values:
I<-rep(c(0,14),10)
If you want a general solution to the problem of filling a vector of
arbitrary length with alternating values:
fill_alternating<-function(len=2,value1=0,value2=1) {
return(rep(c(value1,value2),(len+1)/2)[1:len])
}
There are probably other interpretations as well.
Jim
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