Hi Hp: I'm not sure what you want. Below looks slightly better but if you
want the x-axis
to have better labels, then there is a names.arg argument to barplot. see
?barplot.

I don't know what each of the bins represents but if you want to include
all of those zeros then I don't think there's any way of getting around the
fact that there is so much space in the barplot. Maybe someone else has a
suggestion.

breaks=c(-1.55,-1.50,-1.45,-1.40,-1.35,-1.30,-1.25,-1.20,-1.15,-1.10,-1.05,-1.00,-0.95,-0.90,-0.85,-0.80,-0.75,-0.70,
-0.65,-0.60,-0.55,-0.50,-0.45,-0.40,-0.35,-0.30,-0.25-0.20,-0.15,-0.10,-0.05,0.00,0.05,0.10,0.15,0.20,0.25,0.30,0.35,0.40,
0.45,0.50,0.55)

counts=c(287,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,212,2624,2918,0,0,0,75,36317,4963,0,0,2462,0,0,0,0,0,142)

percentage=counts/sum(counts)
barplot(percentage,xlab="breaks",xlim=c(1,42))


On Mon, Jan 21, 2013 at 7:47 PM, hp wan <huaping....@gmail.com> wrote:

> Ok, that is no problem.
>
>
> 2013/1/22 Mark Leeds <marklee...@gmail.com>
>
>> let me look at but it's probably best to send to the whole list because
>> there are many
>> people on it way more knowledgable than myself. I'm ccing the list and
>> hope you
>> don't mind. my fault for replying privately initially.
>>
>>
>>
>> On Mon, Jan 21, 2013 at 7:36 PM, hp wan <huaping....@gmail.com> wrote:
>>
>>> Thanks for your reply!
>>>
>>>
>>> breaks=c(-1.55,-1.50,-1.45,-1.40,-1.35,-1.30,-1.25,-1.20,-1.15,-1.10,-1.05,-1.00,-0.95,-0.90,-0.85,-0.80,-0.75,-0.70,-0.65,-0.60,-0.55,-0.50,-0.45,-0.40,-0.35,-0.30,-0.25-0.20,-0.15,-0.10,-0.05,0.00,0.05,0.10,0.15,0.20,0.25,0.30,0.35,0.40,0.45,0.50,0.55)
>>>
>>> counts=c(287,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,212,2624,2918,0,0,0,75,36317,4963,0,0,2462,0,0,0,0,0,142)
>>> percentage=counts/sum(counts)
>>> barplot(percentage,xlab=breaks)
>>>
>>> The horizontal value (that is xlabe) looks very ugly. I hope it looks
>>> like the xlab of hist, that is x axis correspond to breaks.
>>>
>>> After ?barplot, I also have no idea to implement it.
>>>
>>> 2013/1/22 Mark Leeds <marklee...@gmail.com>
>>>
>>>> I'm not sure that I understand but can't you just take the data and
>>>> divide it by the sum of the data and plot that ?
>>>>
>>>>
>>>>
>>>> On Mon, Jan 21, 2013 at 6:36 PM, hp wan <huaping....@gmail.com> wrote:
>>>>
>>>>> Thanks for your reply.
>>>>>
>>>>> If I set the probability = FALSE, the column values are corresponding
>>>>> to the refrequency (the numbers of values falling in intervals). I want 
>>>>> the
>>>>> coulumn values are percentage, that is x$counts/sum(x$counts).
>>>>>
>>>>>
>>>>> 2013/1/22 Mark Leeds <marklee...@gmail.com>
>>>>>
>>>>>> Hi: the density integrates to 1 but the actual height of the density
>>>>>> at each point is not less necessarily than 1. for what you want, you 
>>>>>> should
>>>>>> be using probability = FALSE.
>>>>>>
>>>>>> you can do pnorm(x=0,0,1) to see this.
>>>>>>
>>>>>>
>>>>>>
>>>>>>  On Mon, Jan 21, 2013 at 5:18 PM, hp wan <huaping....@gmail.com>wrote:
>>>>>>
>>>>>>>  Hi All,
>>>>>>>
>>>>>>> When carrying out hist(samples,breaks=50,probability=TRUE), the
>>>>>>> column
>>>>>>> values are considerably greater than 1, which seams very
>>>>>>> unreasonable. The
>>>>>>> plot is attached.
>>>>>>>
>>>>>>> I think the column value of the hist plot should correspond to
>>>>>>> x$counts/sum(x$counts)
>>>>>>>    (x=hist(samples,breaks=50,probability=TRUE)). The size of data is
>>>>>>> a
>>>>>>> little bit larger,  causing failure of uploading. If you need the
>>>>>>> data, I
>>>>>>> can email it to you.
>>>>>>>
>>>>>>> Can anyone help me?
>>>>>>>
>>>>>>> Thanks!
>>>>>>>
>>>>>>> Best regares,
>>>>>>>
>>>>>>> Huaping Wan
>>>>>>>
>>>>>>> ______________________________________________
>>>>>>> R-help@r-project.org mailing list
>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>> PLEASE do read the posting guide
>>>>>>> http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
>>>>>>> and provide commented, minimal, self-contained, reproducible code.
>>>>>>>
>>>>>>>
>>>>>>
>>>>>
>>>>
>>>
>>
>

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