Hi m p,
You can use either
apply(fhours, 2, function(x) ifelse(x < 0, x + 24, x)
or
shours <- fhours
shours[shours < 0 ] <- shours[shours < 0 ] + 24
shours
HTH,
Jorge.-
On Sat, Jan 19, 2013 at 4:17 PM, m p <> wrote:
> Hello,
> It should be easu but I cannot figure out how to use apply function. I am
> trying to replace negative values in an array with these values + 24.
> Would appreciate help. Thanks,
> Mark
>
> shours <- apply(fhours, function(x){if (x < 0) x <- x+24})
> Error in match.fun(FUN) : argument "FUN" is missing, with no default
>
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>
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