Hello,
Better yet, with 'agg' as given in my first post:
sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ])
plot(agg$year, agg$population, type = "n")
lapply(seq_along(sp), function(i) lines(sp[[i]]$year,
sp[[i]]$population, col = i))
Hope this helps,
Rui Barradas
Em 17-12-2012 22:00, Rui Barradas escreveu:
Hello,
You want to draw 2 + 67 lines in the same graph? The result should be
confusing...
As for the graph itself, you can use ?matplot, it's meant for that
sort of problem.
Hope this helps,
Rui Barradas
Em 17-12-2012 20:54, eliza botto escreveu:
Dear Arun and Rui,thanks indeed. it really worked out.
i was wondering that can i draw the curve of stations "Sa" , "Ta" and
remaining 67 stations on the same axis, for comparison? more
precisely, taking years on axis, starting from the least year in my
data and ending at latest, while taking population on y-axis?? for
example, in my present data the least year is 1955 and the latest is
1969. For "Sa" the curve must start from 1955 and should end at 1958
and for "Ta" the curve must start from 1966 and should end at 1969.
thankyou very much indeed once again
eliza
Date: Mon, 17 Dec 2012 09:32:54 -0800
From: smartpink...@yahoo.com
Subject: Re: [R] mean of each month in data
To: eliza_bo...@hotmail.com
CC: r-help@r-project.org
HI,
May be this helps:
dat1<-read.table("Eliza.txt",sep="",header=TRUE,stringsAsFactors=FALSE)
library(reshape2)
res<-lapply(split(dat1,dat1$st.),function(x)
dcast(x,month~year,mean,value.var="population_in_million"))
res
$Sa
# month 1955 1956 1957 1958
#1 1 2.400000 NaN NaN NaN
#2 2 2.400000 NaN NaN NaN
#3 3 2.266667 NaN NaN NaN
#4 4 NaN 2.4 NaN NaN
#5 5 NaN 2.4 NaN NaN
#6 6 NaN 2.4 NaN NaN
#7 7 NaN NaN 2.400000 NaN
#8 8 NaN NaN 2.400000 NaN
#9 9 NaN NaN 2.266667 NaN
#10 10 NaN NaN 2.400000 2.4
#11 11 NaN NaN NaN 2.4
#12 12 NaN NaN NaN 2.4
#$Ta
# month 1966 1967 1968 1969
#1 1 2.400000 2.4 2.400000 2.4
#2 2 2.400000 2.4 2.400000 2.4
#3 3 2.266667 2.4 2.266667 2.4
A.K.
----- Original Message -----
From: eliza botto <eliza_bo...@hotmail.com>
To: "r-help@r-project.org" <r-help@r-project.org>
Cc:
Sent: Monday, December 17, 2012 12:11 PM
Subject: [R] mean of each month in data
Dear R users,
[in case the format of email is changed or you dont finf it easy to
understand, i have attached a text file of my question]
i have the data in the following format and i want to convert it in the
format given at the end.
Ta ans Sa are the names of certain cities. there are 69 cities in my
data.
column 1 is representing station name (i am writing the data of only
two cities for simplicity but actually, as i wrote, i have 69 cities
and the actuall table runs down very deep.)
Column 2 represnts the year for which the data is given (Actuall data
for each station is of different length but atleast of 24 years).
Column 3 and 4 reprent the month and the day of the data. obviously
each year has 12 months and each month as different number of days, but
to make table easily understable only 3 months and 3 days of each month
are considered. febrary for leap years should also be considered.
col5 represents population of that city
st. year month day population in million
Ta 1966 1 1 2.4
Ta 1966 1 2 2.4
Ta 1966 1 3 2.4
Ta 1966 2 1 2.4
Ta 1966 2 2 2.4
Ta 1966 2 3 2.4
Ta 1966 3 1 2.3
Ta 1966 3 2 2.2
Ta 1966 3 3 2.3
Ta 1967 1 1 2.4
Ta 1967 1 2 2.4
Ta 1967 1 3 2.4
Ta 1967 2 1 2.4
Ta 1967 2 2 2.4
Ta 1967 2 3 2.4
Ta 1967 3 1 2.4
Ta 1967 3 2 2.4
Ta 1967 3 3 2.4
Ta 1968 1 1 2.4
Ta 1968 1 2 2.4
Ta 1968 1 3 2.4
Ta 1968 2 1 2.4
Ta 1968 2 2 2.4
Ta 1968 2 3 2.4
Ta 1968 3 1 2.3
Ta 1968 3 2 2.2
Ta 1968 3 3 2.3
Ta 1969 1 1 2.4
Ta 1969 1 2 2.4
Ta 1969 1 3 2.4
Ta 1969 2 1 2.4
Ta 1969 2 2 2.4
Ta 1969 2 3 2.4
Ta 1969 3 1 2.4
Ta 1969 3 2 2.4
Ta 1969 3 3 2.4
Sa 1955 1 1 2.4
Sa 1955 1 2 2.4
Sa 1955 1 3 2.4
Sa 1955 2 1 2.4
Sa 1955 2 2 2.4
Sa 1955 2 3 2.4
Sa 1955 3 1 2.3
Sa 1955 3 2 2.2
Sa 1955 3 3 2.3
Sa 1956 4 1 2.4
Sa 1956 4 2 2.4
Sa 1956 4 3 2.4
Sa 1956 5 1 2.4
Sa 1956 5 2 2.4
Sa 1956 5 3 2.4
Sa 1956 6 1 2.4
Sa 1956 6 2 2.4
Sa 1956 6 3 2.4
Sa 1957 7 1 2.4
Sa 1957 7 2 2.4
Sa 1957 7 3 2.4
Sa 1957 8 1 2.4
Sa 1957 8 2 2.4
Sa 1957 8 3 2.4
Sa 1957 9 1 2.3
Sa 1957 9 2 2.2
Sa 1957 9 3 2.3
Sa 1957 10 1 2.4
Sa 1958 10 2 2.4
Sa 1958 10 3 2.4
Sa 1958 11 1 2.4
Sa 1958 11 2 2.4
Sa 1958 11 3 2.4
Sa 1958 12 1 2.4
Sa 1958 12 2 2.4
Sa 1958 12 3 2.4
...
...
uptill 69th station
i want to convert the data in following format
Ta ## matrix for station Ta
1966 1967 1968 1969
AVERAGE OF MONTH 1 AVERAGE OF MONTH 1 AVERAGE OF MONTH 1 AVERAGE OF
MONTH 1
AVERAGE OF MONTH 2 AVERAGE OF MONTH 2 AVERAGE OF MONTH 2 AVERAGE OF
MONTH 2
AVERAGE OF MONTH 3 AVERAGE OF MONTH 3 AVERAGE OF MONTH 3 AVERAGE OF
MONTH 3
........
........
AVERAGE OF MONTH 12 AVERAGE OF MONTH 12 AVERAGE OF MONTH 12 AVERAGE
OF MONTH 12
similar operation are to be done for "Sa" and the remaining 67
stations...
which means i want to have 69 matrices, in which each column (number of
columns should be equal to number of years of data) should contain 12
mean monthly values of population of each year.
thanks in advance
eliza
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and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
