On 28.04.2008, at 16:40, Georg Ehret wrote:
E.g.:
a<-as.data.frame(matrix(rnorm(100),nrow=10,ncol=10))
b<-which(a$V1>0.8)
b
[1] 1 4 6 10
a_indexb<-a[b,]
a_notIndexB<-a[!b,]
nrow(a_notIndexB)
[1] 0
Indexing a on b is not a problem (a_indexb), but how can do get
only the
elements left if I take out the elements indexed with b?
The ! operator only works on BOOLEAN.
ONE possible way to set a_notIndexB is:
a_notIndexB <-a [-1*b, ]
--Hans
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