Thanks Bert for your reply.
I am trying to understand/visualize the Sample Chi-Squared Statistic's
Null distribution. Therefore I need all possible Contingency tables
under Independence case.
What could be better way to visualize that?
Thanks and regards,
On 01 December 2012 20:03:00, Bert Gunter wrote:
Christopher:
Don't do this!
If I understand you correctly, you want FIsher's exact test. This is
already available in R, using far smarter algorithms then you would. See:
?fisher.test
-- Bert
On Sat, Dec 1, 2012 at 5:48 AM, Christofer Bogaso
<bogaso.christo...@gmail.com <mailto:bogaso.christo...@gmail.com>> wrote:
Thanks John for your reply. However still not clear how I should
proceed.
My goal is to generate all possible contingency tables. Basically
I want to see the distribution of Chi-squared Statistic under
independence (NULL).
So I was thinking if I can generate all possible permutation of
integer numbers having sum equal to (8 + 10 + 12 + 6) = 36. Is
there any R function to do that?
Thanks and regards,
On 01-12-2012 18:39, John Kane wrote:
Are you basically asking for all possible permutations of the
table? If so see ?permn in the combinat package.
John Kane
Kingston ON Canada
-----Original Message-----
From: bogaso.christo...@gmail.com
<mailto:bogaso.christo...@gmail.com>
Sent: Sat, 01 Dec 2012 18:10:15 +0545
To: r-help@r-project.org <mailto:r-help@r-project.org>
Subject: [R] Getting all possible contingency tables
Hello all,
Let say I have 2-way contingency table:
Tab <- matrix(c(8, 10, 12, 6), nr = 2)
and the Chi-squared test could not reject the independence:
> chisq.test(Tab)
Pearson's Chi-squared test with Yates'
continuity correction
data: Tab
X-squared = 1.0125, df = 1, p-value = 0.3143
However I want to get all possible contingency tables
under this
independence scenario (one of them would obviously be the
given table
as, we could not reject the independence), and for each
such table I
want to calculate the Ch-sq statistic.
Can somebody help me how to generate all such tables?
Thanks and regards,
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