HI,
I am not sure whether this helps:
temp1<-regmatches(temp, gregexpr("(?:abcd)(1234)", temp)) #your code
substr(unlist(temp1),5,8)
#[1] "1234" "1234"
A.K.
----- Original Message -----
From: Alexander Shenkin <ashen...@ufl.edu>
To: r-help@r-project.org
Cc:
Sent: Friday, November 2, 2012 6:02 PM
Subject: [R] backreferences in gregexpr
Hi Folks,
I'm trying to extract just the backreferences from a regex.
> temp = "abcd1234abcd1234"
> regmatches(temp, gregexpr("(?:abcd)(1234)", temp))
[[1]]
[1] "abcd1234" "abcd1234"
What I would like is:
[1] "1234" "1234"
Note: I know I can just match 1234 here, but the actual example is
complicated enough that I have to match a larger string, and just want
to pass out the backreferenced portion.
Any help greatly appreciated!
Thanks,
Allie
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