I think f0 (from your code) and f1 give identical results
f0 <- function (m = 3, n = 4)
{
stopifnot(m>0, n>0)
mn <- m * n
k <- m + n - 1
X <- matrix(0, mn, k)
for (i in 1:n) {
wr <- 1:m + (i - 1) * m
wc <- rev(1:m + (i - 1))
where <- cbind(wr, wc)
X[where] <- 1
}
X
}
f1 <-
function (m = 3, n = 4)
{
stopifnot(m>0, n>0)
whereInRow <- as.vector(outer(m:1, 0:(n - 1), `+`))
mn <- m * n
X <- matrix(0, mn, m + n - 1)
X[cbind(1:mn, whereInRow)] <- 1
X
}
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -----Original Message-----
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Camarda, Carlo Giovanni
> Sent: Friday, October 26, 2012 8:13 AM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] matrix algebra for constructing a special matrix?
>
> Dear R-users,
>
> would it be a better way to construct the matrix below without using any
> for-loop or
> model.matrix? preferably with some matrix algebra?
>
> Thanks in advance,
> Carlo Giovanni Camarda
>
> ## dimensions
> m <- 3
> n <- 4
> mn <- m*n
> k <- m+n-1
>
> ## with a for-loop
> X <- matrix(0, mn, k)
> for(i in 1:n){
> wr <- 1:m+(i-1)*m
> wc <- rev(1:m+(i-1))
> where <- cbind(wr,wc)
> X[where] <- 1
> }
>
> ## using model.matrix
> ff <- factor(c(outer(m:1, seq(0,m), "+")))
> X1 <- matrix(model.matrix(~-1+ff), mn, k)
>
>
>
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