Hi,
You can also use grep() to subset:
LD<-paste0(rep(rep(c(3,4),each=4),2),c(rep("L",8),rep("D",8)))
set.seed(1)
dat1<-data.frame(LD=LD,value=sample(1:15,16,replace=TRUE))
dat2<-within(dat1,{LD<-as.character(LD)})
dat2[grepl(".*L",dat2$LD),] # subset all L values
dat2[grepl(".*D",dat2$LD),] # subset all D values
dat2[grepl("3D",dat2$LD),]
dat2[grepl("4D",dat2$LD),]
A.K.
----- Original Message -----
From: Charles Determan Jr <deter...@umn.edu>
To: r-help@r-project.org
Cc:
Sent: Friday, September 28, 2012 2:59 PM
Subject: [R] Better way of Grouping?
Hello R users,
This is more of a convenience question that I hope others might find useful
if there is a better answer. I work with large datasets that requires
multiple parsing stages for different analysis. For example, compare group
3 vs. group 4. A more complicated comparison would be time B in group 3 of
group L with B in group 4 of group L. I normally subset each group with
the following type of code.
data=read(...)
#L v D
L=data[LvD %in% c("L"),]
D=data[LvD %in% c("D"),]
#Groups 3 and 4 within L and D
group3L=L[group %in% c("3"),]
group4L=L[group %in% c("3"),]
group3D=D[group %in% c("3"),]
group4D=D[group %in% c("3"),]
#Times B, S45, FR2, FR8
you get the idea
Is there a more efficient way to subset groups? Thanks for any insight.
Regards,
Charles
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