subset(dataFrame, subset) does the equivalent of dataFrame[!is.na(subset) & subset,]. I.e., it treats the NA's in the subset argument the same as FALSEs. Doesn't help(subset) mention this?
By the way, if Renewal is a logical vector, it will be identical to Renewal==TRUE so you may as well leave off the "==TRUE". Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com > -----Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf > Of Mauricio Cornejo > Sent: Monday, August 27, 2012 3:09 PM > To: r-help@r-project.org > Subject: [R] Inexplicably different results using subset vs bracket notation > on logical > variable > > Hi, > > Would anyone have any idea as to why I would obtain completely different > results when > subsetting using the subset function vs bracket notation? > > I have a data frame with 65 variables and 4382 rows. When I use execute the > following > subset command I get the correct results (125 rows) > > subset(df, Renewal==TRUE, 1:2) > > > However, I tried to obtain the same results with bracket notation as > follows. The output > gave me all the rows in the data frame and not just the subset of 125 I was > looking for. > > df[df$Renewal==TRUE, 1:2] > > The 'Renewal' variable is of logical type and is the last (65th) variable in > the data > frame. However, values are either TRUE or NA (there are no 'FALSE' values). > > My attempts at replicating this with a small dummy data set, for including > here, have not > worked (i.e. I don't get an error when I use synthetic data). Any ideas on > what could be > going on? > > Many thanks for any insights anyone may have, > Mauricio > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
