Hello,
Try the following.
x <- c( "Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)",
"Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)",
"Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)",
"Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)" )
lapply(strsplit(x, " - "), function(.x){
s1 <- .x[1]
s2 <- gsub(" \\(.*\\)$", "", .x[2])
s3 <- gsub("^.*(\\(.*\\)$)", "\\1", .x[2])
c(s1, s2, s3)
})
If you want to have the output in the form of matrix or data.frame,
change the above to:
xx <- lapply(...etc...)
mat <- do.call(rbind, xx) # matrix
dat <- data.frame(mat) # data.frame
Hope this helps,
Rui Barradas
Em 16-08-2012 19:41, Sapana Lohani escreveu:
Hi,
I have a table in which one column has the name of the objects as shown below.
Name
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Budlamp-Woodcutter Complex - 15 to 60% slope (60/25/15)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
Terrarossa-Blacktail-Pyeatt Complex - 1 to 40% slope (40/35/15/10)
How can I split the single column into three columns like name
(Budlamp-Woodcutter Complex), slope (15 to 60% slope) and percentage (60/25/15)
thanks
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