Hello,
Not sure if I understand your required output.
Try this:
subset(df,!is.na(match(Reference,Reference[duplicated(Reference)])))
# Publication Reference Id
#1 1 a 1
#2 2 b 2
#3 3 c 3
#4 1 a 4
#7 2 b 7
#8 3 c 8
A.K.
----- Original Message -----
From: Sri krishna Devarayalu Balanagu <balanagudevaray...@gvkbio.com>
To: "r-help@r-project.org" <r-help@r-project.org>
Cc:
Sent: Monday, August 13, 2012 5:17 AM
Subject: [R] How can I get the Ids with Duplicated key and corresponding Ids
with original key?
In this following example Id 4 is duplicated with Id 1.
Like this I want both Ids (Duplicated and Duplicated with). Can anyone help?
df <- data.frame(
"Publication" = c(1, 2, 3, 1, 4, 5, 2, 3),
"Reference" = c("a", "b", "c", "a", "d", "e", "b", "c"),
"Id"= c(1, 2, 3, 4, 5, 6, 7, 8)
)
key <- paste(df$Publication, df$Reference, sep="_")
df.key <- cbind(key, df)
Duplicated.ids <- df.key[duplicated(df.key$key), c("Id")]
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