On Aug 8, 2012, at 3:19 AM, aleksandr russell wrote:
Hello,
I'm working with an array; I'm trying to make it so that an array of
dim(42,2,2) has names whose length corresponds to that of the array,
and am hoping someone with experience with this can see what I'm not
doing correctly:
data11 = array(0,c(41,2,2))
y = lsoda(x0,times,fhn$fn.ode,pars)#This is make.fhn() from colloc
infer package#
y = y[,2:3]
data11<-array(0,c(41,2,2))
m8<-cbind(.29,1:41)
m9<-as.array(m8,dim=c(41,2))
data11[,1,] = y+m9
data11[,2,] = y+m9
I didn't run that code since your difficulties did not seem to have
anything to do with the values inside the array but only with the
dimension labeling.
rownames(data2, do.NULL = FALSE, prefix="row")
What is 'data2'?
varnames=c("V","R")
colnames(data6)=c("one","two")
Ditto... what is 'data6'?
colnames(data10)=colnames(data6)
dimnames(data11)=list(rownames(data2),varnames,colnames(data10))
data11a<-as.array(data11,dimnames=dimnames(data11))
attributes(data11a)
#so this seems to print out the array attributes as they
should be:
For which object?
two sets of two columns each, and the first column of
each set is called 'v' and the second 'r'- no problem#
The data11 object had three dimenstions.
now the analysis from colloc infer(I've put it in below*)
takes this array but will not complete the analysis, saying
"Error in `colnames<-`(`*tmp*`, value = c("V", "R")) :
length of 'dimnames' [2] not equal to array extent"
Here's one way to label a 41 x 2 x 2 array:
> dimnames(data11)<- c(list(X=paste0("X",1:41)), list(Y=paste0("Y",
1:2)), list(Z=paste0("Z",1:2)) )
> attributes(data11)
$dim
[1] 41 2 2
$dimnames
$dimnames$X
[1] "X1" "X2" "X3" "X4" "X5" "X6" "X7" "X8" "X9" "X10"
"X11" "X12" "X13" "X14" "X15" "X16" "X17" "X18" "X19"
[20] "X20" "X21" "X22" "X23" "X24" "X25" "X26" "X27" "X28" "X29" "X30"
"X31" "X32" "X33" "X34" "X35" "X36" "X37" "X38"
[39] "X39" "X40" "X41"
$dimnames$Y
[1] "Y1" "Y2"
$dimnames$Z
[1] "Z1" "Z2"
When I type in
length(dimnames(data11a)[2])
I get the answer:
[1] 1
which seems odd when
dimnames(data11a)[2]
gives
[[1]]
[1] "V" "R"
It is a one element list whose single element is a 2 element vector.
I would like to ask "How can I get the names of the second dimension
of the array(data11a) to have length "2" ?
It seems to me that the analysis will run if I can make this array
have the correct length dimnames
I thank you for your help.
____________
*
fd.data11a = data11a
DEfd11a = Data2fd(fd.data11a, times, bbasis,
fdnames=list(NULL,NULL,varnames))
profile11a.obj=LS.setup(pars,DEfd11a
$coefs,fhn,basisvals=bbasis,lambda,fd.obj=NULL,
more
=NULL,data=data11a,weights=NULL,times=times,quadrature=NULL,eps=1e-6,
posproc=FALSE,poslik=FALSE,discrete=FALSE,names=NULL,sparse=FALSE)
lik = profile11a.obj$lik
proc = profile11a.obj$proc
qwts = rep(1/length(knots),length(knots))
qwts = qwts %*% t(lambda)
weights = array(1,dim(data11a))
likmore = make.id()
likmore$weights = weights
lik = make.SSElik()
lik$more = likmore
lik$bvals = eval.basis(times,bbasis)
procmore = make.fhn()
procmore$weights = qwts
procmore$qpts = qpts
procmore$names = varnames
procmore$parnames = parnames
proc = make.SSEproc()
proc$more = procmore
proc$bvals = list(bvals = eval.basis(procmore$qpts,bbasis,0),
dbvals = eval.basis(procmore$qpts,bbasis,1))
res11a = inneropt(coefs, times=times, data=data11a, lik=lik,
proc=proc,
pars=spars, in.meth='nlminb', control.in=control.out)
--
David Winsemius, MD
Alameda, CA, USA
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