Hi Friends,
I'm new to R ,I have a data frame Z16 which is genarated from another data frame, and I want to add “%” & “$” in row 4 and 5 respectively. when I’m trying using below logic, I’m getting warning message. I'm using R 2.14.2 Version Can anyone help me out on this. Note: Initially i used tranfrom function to do some calculations,where ever it should give zero,its giving NaN,i used Replace function to replace NaN with Zero(0) Z16: Summary G Y R T Accts 582 644 0 1226 AcctCov 230 165 0 395 Cov% 40 26 0 32 UnCov% 60 74 0 68 EqVol11$MM 8.5 10.6 0 19.1 Using this logic: Z16[5,2:5]<-paste("$",Z16[5,2:5],sep="") Z16[3,2:5]<-paste(Z16[3,2:5],"%",sep="") Z16[4,2:5]<-paste(Z16[4,2:5],"%",sep="") Getting this Warning: In `[<-.factor`(`*tmp*`, iseq, value = c(3L, 1L, 2L, 4L, NA)) invalid factor level, NAs generate Final result: Summary G Y R T Accts 582 644 0 1226 AcctCov 230 165 0 395 Cov% 40% 26% 0% 32% UnCov% 60% 74% 0% 68% EqVol11$MM $8.50 $10.60 $0 $19.10 Thanks in Advance. Thanks, Namit -- View this message in context: http://r.789695.n4.nabble.com/Can-any-one-help-me-on-this-Issue-tp4638664.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.