If you want that output.....
substr()
Can help in your task too.
I can not help with regular expression, I will learn too.
> Date: Tue, 24 Jul 2012 13:36:25 -0400
> From: bayespoker...@gmail.com
> To: r-help@r-project.org
> Subject: [R] Regular Expression
>
> Hi--
>
> I have three columns in an input file:
> MONTH QUARTER YEAR
> 2012-07 2012-3 2012
> 2001-07 2001-3 2001
> 2002-01 2002-1 2002
>
> I want to make output like so:
> MONTH QUARTER YEAR
> 07 3 2012
> 07 3 2001
> 01 1 2002
>
> I was having some trouble getting the regular expression to work. I think
> it should be something like the following:
> tmp <- uncurated$MONTH
> *tmp <- gsub("[^-\\d\\d]","",tmp,perl=TRUE)*
> *tmp[tmp=="-"] <- ""*
> *curated$MONTH <- tmp*
> *
> *
> tmp <- uncurated$QUARTER
> *tmp <- gsub("[^-\\d]","",tmp,perl=TRUE)*
> *tmp[tmp=="-"] <- ""*
> *curated$QUARTER <- tmp*
> *
> *
> *but it's not quite working. I want to be able to isolate any digits that
> occur after the hyphen and to delete everything before and including the
> hyphen. Would greatly appreciate any clarification anyone can provide.*
>
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>
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