Hello,
You don't need an optimzation routine to know that the maximum of this
function is +Inf. It's attained at z = 0+ (when z converges to zero by
positive values).
This breaks the R function optim(), by the way. It
" needs finite values of 'fn' "
Hope this helps,
Rui Barradas
Em 08-07-2012 10:15, Raghuraman Ramachandran escreveu:
guRus!
I have a function f = exp(x^2-y+(1/z))
Also, x can take values from 1 to 37, y from 2 to 20 and Z from -13 to 51.
How can I find the maximum of f using any of the optimization functions
please?
Is there a way to store the possible values of x, y and Z in a single
variable like in a List or in a multi-dimensional array?
Thanks for your help
Raghu
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