The space is for a different reason, strsplit doesn't put the split
pattern in the result, so if a space is included it will be
automatically deleted. For instance in "XXY (mat harry)" without the
space it would become "XXY " and "mat harry)" but we want "XXY" so
include the space in the pattern.
Another example, this one artificial:
"123AB456" ---> "123" and "456"
strsplit("123AB456", "B") ---> "123A" and "456"
So include the "A" in the pattern. It's _exactly_ the same thing.
Rui Barradas
Em 07-07-2012 23:21, John Kane escreveu:
Ah, I think Mark may have it. See my earlier post. Why the space?
John Kane
Kingston ON Canada
-----Original Message-----
From: ruipbarra...@sapo.pt
Sent: Sat, 07 Jul 2012 23:12:46 +0100
To: marklee...@gmail.com
Subject: Re: [R] Splitting a character vector.
Oh, right!
The close parenthesis isn't doing nothing in the result, t could be done
after but since we're to it...
Rui Barradas
Em 07-07-2012 23:10, Mark Leeds escreveu:
Hi Rui: I think he's asking about your replacement with blanks.
On Sat, Jul 7, 2012 at 6:08 PM, Rui Barradas <ruipbarra...@sapo.pt
<mailto:ruipbarra...@sapo.pt>> wrote:
Hello,
Sorry, but I don't understand, you're asking about 4 single quotes,
the double quotes in open.par are just opening and closing the
pattern, a character string.
Rui Barradas
Em 07-07-2012 23:03, John Kane escreveu:
Thanks Rui
It works perfectly so far on the test and real data.
The annoying thing is that I had tried , or thought I'd tried
the open.par format and keep getting an error.
It looks like I had failed to add the '''', in the term.
What is it doing?
John Kane
Kingston ON Canada
-----Original Message-----
From: ruipbarra...@sapo.pt <mailto:ruipbarra...@sapo.pt>
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrid...@inbox.com <mailto:jrkrid...@inbox.com>
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must
be escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe
something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a
solution to a simple
problem.
I have a vector with some character values that I want
to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP
(joe blow)", "ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP",
"ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with
strsplit but
either I am misunderstanding the function or don't know
how to escape a
"(" properly in an effort to at least get "XXY" "(mat
harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
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