Thanks Petr for the reply.

Let me do implementation and see how how goes.

Enjoy your vacation.
Rest fine
Khris

On Jul 4, 2012, at 8:25 PM, Petr Savicky [via R] wrote:

> On Mon, Jul 02, 2012 at 06:11:37AM -0700, khris wrote:
> 
> > Hi, Petr, 
> > 
> > > 
> > > Hi Khris: 
> > > 
> > > If i understand the problem correctly, you have a list of (x,y) 
> > > coordinates, where 
> > > some sensor is located, but you do not know, which sensor is there. The 
> > > database 
> > > contains data for each sensor identified in some way, but you do not know 
> > > the 
> > > mapping between sensor identifiers from the database and the (x,y) 
> > > coordinates. 
> > > Is this correct? 
> > 
> > Yes. 
> > 
> > > 
> > > > So I modelled the problem as inexact match between 2 Graphs. Since the 
> > > > best 
> > > > package on Graphs i.e. iGraph does not have any function for Graph 
> > > > matching 
> > > 
> > > I think, the problem is close to 
> > > 
> > >   http://en.wikipedia.org/wiki/Graph_isomorphism
> > > 
> > > You have estimates of the distances between the sensors using identifiers 
> > > from the database. So, you know, which pairs of sensors are close. This 
> > > is 
> > > one graph. The other graph is the graph of closeness between the known 
> > > (x,y) 
> > > coordinates. You want to find a mapping between the vertices of these two 
> > > graphs, which preserves edges. 
> > 
> > Yes, I agree the problem is more into Graph theoretic domain to be more 
> > precise inexact graph matching whose generalization is the Graph 
> > Isomorphism problem. The problem is more general than Graph Isomorphism. 
> > Let me define the problem more formally. 
> > 
> >  We have 2 weighted undirected graphs. In one graph I know the distance of 
> > every vertex from every other vertex whereas in another graph I know only 
> > which vertices are close to a given vertex. So I know the neighboring 
> > vertices given a vertex. So the distance matrix of other Graph is 
> > incompletely known. So the question is can I find the best alignment 
> > between the 2 graphs. 
> > 
> > Ex:- G1 is know the complete distance matrix. For G2, if there are four 
> > vertices let's say (v1, v2, v3 v4) the I know edge weight (v1,v2) and 
> > (v1,v3)  but have no information of edge weight(v1,v4). Similarly I know 
> > about (v2,v3) but no information about edge weights (v2,v4) or (v3,v4). 
> > 
> > So I was thinking of not to model it as general inexact Graph matching 
> > problem for then the complexity n^4. It seems the best way to model the 
> > solution is to consider only edges with are at distance of 1 unit i.e. 
> > closest edge from every vertex and not every edge from the given vertex. 
> > This will bring down the complexity from n^4 to 6*6*n^2 assuming every 
> > vertex has atmost 6 neighboring vertex. Quadratic complexity seems 
> > manageable. Ofcourse now the solution become lot more sensitive to the 
> > errors in Graph G2. Assuming best case if I have no errors in G2 i.e. for 
> > every vertex I know correctly it's closest neighbored in the rectangular 
> > grid then optimizing distance between G1 and G2 should give me best correct 
> > alignment. This seems to be the best approach under current circumstance. 
> > 
> > As far as implementation goes I think I still have to use optimization 
> > package since there are not any readily and freely available function for 
> > inexact graph matching. 
> > 
> > Petr how do you feel about it. Appreciate your feedback.
> 
> Hi. 
> 
> I am on vacations with only occasional access to the internet. 
> 
> One way to solve your problem is to formulate it in a way, 
> in which it can be solved by some existing solver. I do not 
> know, whether this is possible. Look at self-organizing maps 
> (Kohonen maps). They try to map points with unknown mutual 
> relationships to a 2 dimensional grid. However, i am not sure, 
> whether the input to this method is suitable for your problem. 
> 
> Another way is to write your own program. I sent some suggestions 
> in this direction in a previous email. If you want, we can discuss 
> this in more detail next week, when i am back from vacations. 
> 
> All the best, Petr. 
> 
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