Hello,
Try regular expressions instead.
In this data.frame, I've changed row nr.4 to have a row with 'D' as
first non-zero character.
dd <- read.table(text="
ch count
1 0000000000D0000000000000000000000000000000000000 0.007368
2 0000000000d0000000000000000000000000000000000000 0.002456
3 000000000T00000000000000000000000000000000000000 0.007368
4 000000000DT0000000000000000000000000000000000000 0.007368
5 000000000T00000000000000000000000000000000000000 0.002456
6 000000000Td0000000000000000000000000000000000000 0.002456
7 00000000T000000000000000000000000000000000000000 0.007368
8 00000000T0D0000000000000000000000000000000000000 0.007368
9 00000000T000000000000000000000000000000000000000 0.002456
10 00000000T0d0000000000000000000000000000000000000 0.002456
", header=TRUE)
dd
i1 <- grepl("^([0D]|[0d])*$", dd$ch)
i2 <- grepl("^0*[Dd]", dd$ch)
dd[!i1, ]
dd[!i2, ]
dd[!(i1 | i2), ]
Hope this helps,
Rui Barradas
Em 02-07-2012 23:48, Claudia Penaloza escreveu:
I would like to remove rows from the following data frame (df) if there are
only two specific elements found in the df$ch character string (I want to
remove rows with only "0" & "D" or "0" & "d"). Alternatively, I would like
to remove rows if the first non-zero element is "D" or "d".
ch count
1 0000000000D0000000000000000000000000000000000000 0.007368;
2 0000000000d0000000000000000000000000000000000000 0.002456;
3 000000000T00000000000000000000000000000000000000 0.007368;
4 000000000TD0000000000000000000000000000000000000 0.007368;
5 000000000T00000000000000000000000000000000000000 0.002456;
6 000000000Td0000000000000000000000000000000000000 0.002456;
7 00000000T000000000000000000000000000000000000000 0.007368;
8 00000000T0D0000000000000000000000000000000000000 0.007368;
9 00000000T000000000000000000000000000000000000000 0.002456;
10 00000000T0d0000000000000000000000000000000000000 0.002456;
I tried the following but it doesn't work if there is more than one
character per string:
df <- df[!df$ch %in% c("0","D"),]
df <- df[!df$ch %in% c("0","d"),]
Any help greatly appreciated,
Claudia
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