Hi Sebastian,
Probably, but I suspect the "correct" answer is simply do not do it
that way. Instead of:
test1 <- 1:10
test2 <- 11:20
...
test5 <- 41:50
testt5[7] <- .435
do
test <- list(1:10, 11:20, 21:30, 31:40, 41:50)
then it is as easy as
test[[5]][7] <- .435
Cheers,
Josh
On Wed, Jun 20, 2012 at 12:59 AM, Leuzinger Sebastian
<sebastian.leuzin...@env.ethz.ch> wrote:
> Dear all
>
> Is there a more efficient way of achieving the following (assigning to an
> indexed vector in a loop):
>
> test5 <- 1:10
> eval(parse(text=paste("test",5,"[",7,"]<- ",0.435,sep="")))
>
> this works, but it is probably very slow.
>
> Thanks
> Sebastian Leuzinger
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--
Joshua Wiley
Ph.D. Student, Health Psychology
Programmer Analyst II, Statistical Consulting Group
University of California, Los Angeles
https://joshuawiley.com/
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