On Wed, Jun 6, 2012 at 12:54 PM, emorway <emor...@usgs.gov> wrote: > useRs- > > I'm attempting to scan a more than 1Gb text file and read and store the > values that follow a specific key-phrase that is repeated multiple time > throughout the file. A snippet of the text file I'm trying to read is > attached. The text file is a dumping ground for various aspects of the > performance of the model that generates it. Thus, the location of > information I'm wanting to extract from the file is not in a fixed position > (i.e. it does not always appears in a predictable location, like line 1000, > or 2000, etc.). Rather, the desired values always follow a specific phrase: > " PERCENT DISCREPANCY =" > > One approach I took was the following: > > library(R.utils) > > txt_con<-file(description="D:/MCR_BeoPEST - Copy/MCR.out",open="r") > #The above will need to be altered if one desires to test code on the > attached txt file, which will run much quicker > system.time(num_lines<-countLines("D:/MCR_BeoPEST - Copy/MCR.out")) > #elapsed time on full 1Gb file took about 55 seconds on a 3.6Gh Xeon > num_lines > #14405247 > > system.time( > for(i in 1:num_lines){ > txt_line<-readLines(txt_con,n=1) > if (length(grep(" PERCENT DISCREPANCY =",txt_line))) { > pd<-c(pd,as.numeric(substr(txt_line,70,78))) > } > } > ) > #Time took about 5 minutes > > The inefficiencies in this approach arise due to reading the file twice > (first to get num_lines, then to step through each line looking for the > desired text). > > Is there a way to speed this process up through the use of a ?scan ? I > wan't able to get anything working, but what I had in mind was scan through > the more than 1Gb file and when the keyphrase (e.g. " PERCENT > DISCREPANCY = ") is encountered, read and store the next 13 characters > (which will include some white spaces) as a numeric value, then resume the > scan until the key phrase is encountered again and repeat until the > end-of-the-file marker is encountered. Is such an approach even possible or > is line-by-line the best bet? > > http://r.789695.n4.nabble.com/file/n4632558/MCR.out MCR.out
Try this: g <- function(url, string, from, to, ...) { L <- readLines(url) matched <- grep(string, L, value = TRUE, ...) as.numeric(substring(matched, from, to)) } > url <- "http://r.789695.n4.nabble.com/file/n4632558/MCR.out" > g(url, "PERCENT DISCREPANCY = ", 70, 78, fixed = TRUE) [1] NA 0.00 -0.01 NA 0.00 -0.01 -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.