David Winsemius wrote > > This is making me think you really have multiple observation on the > same individuals (and that persons make transitions from one state to > another as a result of the passage of time. That needs a more complex > analysis than "simple" logistic regression. You might consider posting > a more complete description of the study on the SIG Mixed Effects > mailing list. > > -- > David. >
No, I haven't. Individuals are birds marked with an unique alphanumeric code that gives me information on their gender (sometimes I have this data sometime I haven't), and their birth date (as a consequence also the age). There are no multiple observations of the same individual. Anyway, I believe I have not been answered to the main question: when using anova with test "Chisq" between two models, is the difference in deviance between the two models interpretable as the Chi Square value and the difference in df interpretable as the df of the Chi square test? For instance, given: > anova(mod4,update(mod4,~.-cohort),test="Chisq") Analysis of Deviance Table Model 1: site ~ cohort Model 2: site ~ 1 Resid. Df Resid. Dev Df Deviance P(>|Chi|) 1 993 1283.7 2 1002 1368.2 -9 -84.554 2.002e-14 *** --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 Is 84.554 taken as the Chi square value, 9 as the df of the test and the p-value depending on these two values? -- View this message in context: http://r.789695.n4.nabble.com/Chi-square-value-of-anova-binomialglmnull-binomglmmod-test-Chisq-tp4632293p4632504.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
