Thanks all, that worked! Yes, it should be for (i in 1:length(a)) a[i]<- scalar * a[i] * i
And now is... a <- a * scalar * seq_along(a) That is almost as cool as the PERL programming language :-) 2012/6/4 Rui Barradas <ruipbarra...@sapo.pt> > Hello, > > Just learning the alphabet? If yes, there's a difference between 'v' and > 'a'. > > Now more seriously. Your description and your loop don't do the same. > > Description: > vm <- scalar * v * seq_along(v) > > Loop: > a <- scalar * a > > Also, seq_along is the way to do it, it works even if length(a) == 0. > > Hope this helps, > > Rui Barradas > > Em 04-06-2012 21:25, Erdal Karaca escreveu: > >> (Just learning R) >> >> I have this vector: >> >> v<- c(1:10) >> >> Now, I want to multiply each element of that vector with a scalar value >> multiplied with its index: >> >> vm<- v * scalar * indexOfCurrentElementOf_v >> >> Is that possible without using a loop? >> >> In a loop I would do this: >> >> for (i in 1:length(a)) a[i]<- scalar * a[i] >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
