Hello,

Or maybe put the data frames in a list

df.list <- lapply(seq_len(filenames), read.csv, ...) # '...other...' are options you might want to pass, (like headers=TRUE)
names(df.list) <- data_names

Now access the data frames by number in the list or by name in data_names.

Hope this helps,

Rui Barradas
Em 25-05-2012 20:08, Nutter, Benjamin escreveu:
For example:

myDir<- "some file path"
filenames<- list.files(myDir)
filenames<- filenames[grep("[.]csv", filenames)]

data_names<- gsub("[.]csv", "", filenames)

for(i in 1:length(filenames)) assign(data_names[i], read.csv(file.path(myDir, 
filenames[i])))

  Benjamin Nutter |  Biostatistician     |  Quantitative Health Sciences
   Cleveland Clinic    |  9500 Euclid Ave.  |  Cleveland, OH 44195  | (216) 
445-1365


-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On 
Behalf Of Kevin Wright
Sent: Friday, May 25, 2012 2:55 PM
To: HJ YAN
Cc: r-help@r-project.org
Subject: Re: [R] Reading a bunch of csv files into R

See ?dir

Assign the value to a vector and loop over the elements of the vector.

Kevin


On Fri, May 25, 2012 at 12:16 PM, HJ YAN<yhj...@googlemail.com>  wrote:
Dear R users


I am struggling from a data importing issue:

I have some hundreds of csv files needed to be read into R for futher
analysis. All those csv files are named in one of the three formats:

(1) strings: e.g. London_Oxford street
(2) Integer: e.g. 1234_5678
(3) combined: e.g. London_1234

I intend to use read.csv("xxxx_xxx.csv") but I only dealt with sigle
documents before and if there are only no more than 20 files, I do not
bother to search a more efficient way.


Is there any claver way that I do not have to type in all these
hundreds names by hand, maybe using a R package or write some code in
some other languages if it is not too difficult to learn.

Any thoughts/hints please??

Many thanks in advance!

HJ

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