Hello, Your doubt is a frequent one. 'col_name' is a character vector, it's elements are character strings, not symbols. These are all equivalent, and are what you want.
raw_data[[ col_name[i] ]] # using a list-like syntax (data.frame subclasses list) raw_data[ , col_name[i] ] # seems more like a rows&columns data structure raw_data[ , i ] # using the column number Two notes. One, it's better to use seq.int than to use 1:length(...) because if the length is zero, the second form will become the vector 1:0 == c(1, 0) and your loop will execute with wrong results. See the help page for seq.int ?seq.int seq.int(length(col_name) - 2) The other, you're rewriting the value of 'chisqtest' every time through the loop. If you only want the test results inside it, that's ok, if not, maybe you could keep the results in a list, using something like chisqtest <- vector("list", length(col_name) - 2) # create the list before the loop for (i in seq.int(length(col_name) - 2)) { [... loop code ...] chisqtest[[ i ]] <- chisq.test(tbl) } Hope this helps, Rui Barradas anindya55 wrote > > I have a dataset called "raw-data" . I am trying to use the following code > - > > > col_name<-names(raw_data) > for (i in 1:(length(names(raw_data))-2)) > { > tbl=table(raw_data$Pay.Late.Dummy, raw_data$col_name[i]) > > chisqtest<-chisq.test(tbl) > } > > > Say the 1st column of my raw_data is Column1. The idea is when i=1 then > raw_data$col_name[i] will automatically become raw_data$Column1 , which is > not happening. Kindly help? > -- View this message in context: http://r.789695.n4.nabble.com/Replace-a-variable-by-its-value-tp4630734p4630736.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.